Answer: The amount of carbon-14 remaining after 4 years is 99.95 grams.
Step-by-step explanation:
Hi, to answer this question we simply have to substitute t=4 in the equation given and solve for c.
c= 100 (0.99988)^t
c =100 (0.99988)^4
c = 100 x 0.999520086
c= 99.95200864 ≅99.95 grams (rounded)
The amount of carbon-14 remaining after 4 years is 99.95 grams.
Feel free to ask for more if needed or if you did not understand something.
7/8 -1/4
= 7/8 -2/8
= 5/8
The final answer is 5/8~
Answer:
1. C. cylindrical coordinates
2 A. spherical coordinates
3. A. spherical coordinates
4. D. Cartesian coordinates
5 B. polar coordinates
Step-by-step explanation:
USE THE BOUNDARY INTERVALS TO IDENTIFY
1. ∭E dV where E is:
x^2 + y^2 + z^2<= 4, x>= 0, y>= 0, z>= 0 -- This is A CYLINDRICAL COORDINATES SINCE x>= 0, y>= 0, z>= 0
2. ∭E z^2 dV where E is:
-2 <= z <= 2,1 <= x^ 2 + y^2 <= 2 This is A SPHERICAL COORDINATES
3. ∭E z dV where E is:
1 <= x <= 2, 3<= y <= 4,5 <= z <= 6 -- This is A SPHERICAL COORDINATES
4. ∫10∫y^20 1/x dx ---- This is A CARTESIAN COORDINATES
5. ∬D 1/x^2 + y^2 dA where D is: x^2 + y^2 <=4 This is A POLAR COORDINATES
Answer:
Using tally marks
Step-by-step explanation:
Missing information;
Number of pets are;
3,0,1,4,4,1,2,0,2,2,0,2,0,1,3,1,2,1,1,3
Find;
Ungroups frequency distribution table
Computation:
<u>Number of pets Tally Frequency</u>
0 IIII 4
1 IIIII I 6
2 IIIII 5
3 III 3
4 II 2
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