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hoa [83]
4 years ago
13

Is 45/5 equal to a whole number

Mathematics
1 answer:
scoray [572]4 years ago
5 0
Yes, indeed it does equal a whole number. 45/5 equals 9, which is a whole number. Whole numbers are numbers that you count up from and including 0 (0,1,2,3,4,5,6...)

You get 9 because 45/5 is the same as 45 divided by 5 which is 9.
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Solve the equation. x5 x5 + 9 = 4
xeze [42]
Idk if you wrote it incorrectly. but im just going to avoid the first 5× soooo x= -1
8 0
4 years ago
Write a story problem to represent 1/2 divided by 3
myrzilka [38]
One day, a girl named,"Amanda" wanted to share cookies in between 3 of her best friends.However, she only had 1/2 of her cookie left. So she divided her cookie by 3 to share her cookie with every single friend.
3 0
3 years ago
Three forces act on an object. Two of the forces are at an angle of 95◦ to each other and have magnitudes 35 N and 7 N. The thir
Cerrena [4.2K]

We want to find \vec F_4 such that the object needs is in equilibrium:

\vec F_1+\vec F_2+\vec F_3+\vec F_4=\vec0

We're told that F_1=35\,\mathrm N, F_2=7\,\mathrm N, and F_3=9\,\mathrm N. We also know the angle between \vec F_1 and \vec F_2 is 95º, which means

\vec F_1\cdot\vec F_2=F_1F_2\cos95^\circ=245\cos95^\circ

\vec F_3 is perpendicular to both \vec F_1 and \vec F_2, so \vec F_1\cdot\vec F_3=\vec F_2\cdot\vec F_3=0.

If we take the dot product of \vec F_1 with the sum of all four vectors, we get

\vec F_1\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0

\vec F_1\cdot\vec F_1+\vec F_1\cdot\vec F_2+\vec F_1\cdot\vec F_3+\vec F_1\cdot\vec F_4=0

{F_1}^2+\vec F_1\cdot\vec F_2+0+\vec F_1\cdot\vec F_4=0

\implies\vec F_1\cdot\vec F_4=-\left({F_1}^2+\vec F_1\cdot\vec F_2\right)

We can do the same thing with \vec F_2 and \vec F_3:

\vec F_2\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0

\implies\vec F_2\cdot\vec F_4=-\left(\vec F_1\cdot\vec F_2+{F_2}^2\right)

\vec F_3\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0

\implies\vec F_3\cdot\vec F_4=-{F_3}^2

Finally, if we do this with \vec F_4, we get

\vec F_4\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0

\implies{F_4}^2=-\left(\vec F_1\cdot\vec F_4+\vec F_2\cdot\vec F_4+\vec F_3\cdot\vec F_4\right)

\implies{F_4}^2=-\left(-\left({F_1}^2+\vec F_1\cdot\vec F_2\right)-\left(\vec F_1\cdot\vec F_2+{F_2}^2\right)-{F_3}^2\right)

\implies F_4=\sqrt{{F_1}^2+{F_2}^2+{F_3}^2+2(\vec F_1\cdot\vec F_2)}

\implies\boxed{F_4\approx36.2\,\mathrm N}

7 0
3 years ago
Factor: -49x^2+ 7y^2 + 133
prisoha [69]

Answer:

-7 (7x^2-y^2-19)

Step-by-step explanation:

5 0
3 years ago
Identify which table shows a direct variation? A. Table 1 only B. Table 2 only C. Both tables D. Neither table
Digiron [165]
Hello.

A direct variation is when one variable affects the other variable. Let's take a look at each table that we've been given.

Table 1:
x = 1, y = 19
x = 2, y = 38
x = 3, y = 57
This table seems to have the effect of when x goes up by 1, y goes up by 19;
1, 19; 2, 38; 3, 57; and so on.

This means at least table 1 has a direct variation with it's variables. But let's continue with table 2 as we have answer choices that say both, neither, or individual tables have direct variations.

Table 2:
x = 5, y = 48
x = 6, y = 72
x = 7, y = 84
This doesn't appear to have a constant direct variation, aside from the first two sets of variables.

This leaves us with our answer:
A.) Table 1 only

I hope this helps!
7 0
4 years ago
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