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ss7ja [257]
3 years ago
14

What is the least common multiple of 28 and 8

Mathematics
2 answers:
nordsb [41]3 years ago
6 0
LEAST COMMON MULTIPLE is 56

hope this helped☺

Mazyrski [523]3 years ago
4 0
28: 22 7
8: 222
-------------------
LCM: 2227
The least common multiple(LCM) is:
2 x 2 x 2 x 7= 56
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The area of a square can be found using the equation A=s^2, where A is the area and s is the measure of one side of the square.
MaRussiya [10]
A = 81 square in.

s = sqrt(A)

s = sqrt(81)

s = 9 in.
8 0
3 years ago
The area of a trapezium is 800 cm2
svlad2 [7]

Answer:

The distance between the parallel sides is 20cm.

Step-by-step explanation:

Area of a trapezoid:

A=\frac{a+b}{2}\times h

where a and b are the 2 bases, and h is the height. The value we're trying to find here is the height.

3 of the 4 variables in this equation are already given:

A = 800

a = 48

b = 32

Just plug those in and solve for h:

\rightarrow 800=\frac{48+32}{2}\times h\\\rightarrow 800=\frac{80}{2}\times h\\\rightarrow 800=40\times h\\\rightarrow 800\div40=h\\\rightarrow h=20

5 0
3 years ago
Read 2 more answers
The mean of x y and z is 20. find the mean of x-5 y+4 z-5
Dafna11 [192]

Answer:

18

Step-by-step explanation:

Sum of x, y and z = 20 × 3

                             = 60

x-5+y+4+z-5 = 60-5+4-5

                    = 54

Mean of x-5, y+4 and z-5

= 54 ÷ 3

= 18

7 0
2 years ago
42:28
gogolik [260]

Answer:

The statements about arcs and angles that are true in the figure are;

1) ∠EFD ≅ ∠EGD

2) \overline{ED}\cong \overline{FD}

3) mFD = 120°

Step-by-step explanation:

1) ∠ECD + ∠CEG + ∠CDG + ∠GDE = 360° (Sum of interior angle of a quadrilateral)

∠CEG = ∠CDG = 90° (Given)

∠GDE = 60° (Given)

∴ ∠ECD = 360° - (∠CEG + ∠CDG + ∠GDE)

∠ECD = 360° - (90° + 90° + 60°) = 120°

∠ECD = 2 × ∠EFD (Angle subtended is twice the angle subtended at the circumference)

120° = 2 × ∠EFD

∠EFD = 120°/2 = 60°

∠EFD ≅ ∠EGD

∠ECD = 120°

∠EGD = 60°

∴∠EGD ≠ ∠ECD

2) Given that arc mEF ≅ arc mFD

Therefore, ΔECF and ΔDCF are isosceles triangles having two sides (radii EC and CF in ΔECF and radii EF and CD in ΔDCF

∠ECF = mEF = mFD = ∠DCF (Given)

∴ ΔECF ≅ ΔDCF (Side Angle Side, SAS, rule of congruency)

\\ \overline{EF}\cong \overline{FD} (Corresponding Parts of Congruent Triangles are Congruent, CPCTC)

∠FED ≅ ∠FDE (base angles of isosceles triangle)

∠FED + ∠FDE + ∠EFD = 180° (sum of interior angles of a triangle)

∠FED + ∠FDE = 180° - ∠EFD = 180° - 60° = 120°

∠FED + ∠FDE = 120° = ∠FED + ∠FED (substitution)

2 × ∠FED  = 120°

∠FED = 120°/2 = 60° = ∠FDE

∴ ∠FED = ∠FDE = ∠EFD =  60°

ΔEFD  is an equilateral triangle as all interior angles are equal

\\ \overline{EF}\cong \overline{FD}\cong \overline{ED} (definition of equilateral triangle)

\overline{ED}\cong \overline{FD}

3) Having that ∠EFD = 60° and ∠CFE = ∠CFD (CPCTC)

Where, ∠EFD = ∠CFE + ∠CFD (Angle addition)

60° = ∠CFE + ∠CFD = ∠CFE + ∠CFE (substitution)

60° = 2 × ∠CFE

∠CFE =60°/2 = 30° = ∠CFD

\overline{CF}\cong \overline{CD} (radii of the same circle)

ΔFCD is an isosceles triangle (definition)

∠CFD ≅ ∠CDF (base angles of isosceles ΔFCD)

∠CFD + ∠CDF + ∠DCF = 180°

∠DCF = 180° - (∠CFD + ∠CDF) = 180° - (30° + 30°) = 120°

mFD = ∠DCF (definition)

mFD = 120°.

5 0
3 years ago
Solve for X.<br> - 3x + 2 = -10x + 30
Nataly_w [17]

Answer:

x = 4

Step-by-step explanation:

-3x + 2 = -10x + 30

Add 10x to both sides and you get

7x + 2 = 30

Subtract 2 from both sides and you get

7x = 28

Divide both sides by 7 to get x by itself and you get

x = 4

Reminder whatever you do to one side you have to do to the other side!

Hope this helps!

3 0
3 years ago
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