Question

When a fraction of 17 is taken away from 17 , what remains exceeds one-third of seventeen by six.

Answer 1

Answer:

The fraction is less than $\frac{17}{18}$.

Step-by-step explanation:

Let the fraction is $\frac{1}{n}$.

Given that when the fraction of 17 is subtracted from 17 itself, then the remaining will be greater than one-third of 17 divided by six.

Therefore, by the given condition,  

$17 - \frac{17}{n} > \frac{1}{3}(\frac{17}{6} )$

⇒ $17 - \frac{17}{n} > \frac{17}{18}$

⇒ $1 - \frac{1}{n} > \frac{1}{18}$

⇒ $\frac{1}{n} < 1 - \frac{1}{18}$

⇒ $\frac{1}{n} < \frac{17}{18}$

Therefore, the fraction is less than $\frac{17}{18}$. (Answer)