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2 years ago

JUST READ THE ATTACHMENT

Mathematics

2 answers:

Romashka-Z-Leto [24]2 years ago

8 0

The anwser is (A 3,4,5)

astra-53 [7]2 years ago

7 0

Your answer would be 3,4,5

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There are 200 9th graders in the freshman class. 2/5 of the students are girls. How

alekssr [168]

Answer: 80

Step-by-step explanation:

7 0

2 years ago

Suppose the population of all public universities shows the annual parking fee per student is $110, with a standard deviation of

vampirchik [111]

The probability would be 0.9738.

We first find the z-score for each end of this interval:

z = (x-μ)/(σ/√n) = (100-110)/(18/√49) = -10/(18/7) = -3.89

z = (x-μ)/(σ/√n) = (115-110)/(18/√49) = 5/(18/7) = 1.94

Using a z-table (http://www.z-table.com) we see that the probability that a score is less than the first z-score is 0. The probability under the curve to the left of, less than, the second z-score is 0.9738. Subtracting these we find the area between them:
0.9738 - 0 = 0.9738.

3 0

3 years ago

The graph shows the number of pages to read after x days. Answer the 4 points

yanalaym [24]

Answer:

Step-by-step explanation:

•y-intercept is the 200 pages she has to read to begin with

•x-intercept on day 16 means she has finished reading all the pages, there are

zero pages left

•there are 100 pages left after 8 days

• the line is straight (no change in slope) so the reading rate was consistent over the 16 days.

7 0

2 years ago

How many oranges are in a crate if the price of a crate of oranges is $1.60 and the price of oranges is $0.20 per pound and ther

Shtirlitz [24]

Answer:

7 oranges

Step-by-step explanation: 3 oranges in a pound 0.20 cents per pound. 60 cents per pound add it up.

8 0

3 years ago

On a single roll of a pair of dice, what are the odds against rolling a sum of 12?

o-na [289]

Answer:

$\frac{1}{35}$

Step-by-step explanation:

On a single roll of a pair of dice. When a pair of dice are rolled the possible outcomes are as follows:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

The number of outcomes that gives us 12 are (6,6). There is only one outcome that gives us sum 12.

Total outcomes = 36

Odd against favor = $\frac{non \ favorable\ outcomes}{favorable \ outcomes}$

Number of outcomes of getting sum 12 is 1

Number of outcomes of not getting sum 12 is 36-1= 35

odds against rolling a sum of 12= $\frac{1}{35}$

3 0

3 years ago