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Pani-rosa [81]
3 years ago
5

Jocelyn's swimming pool is 14.75ft long by 7.5 ft wide. The community center swimming pool is 200 square feet larger than Jocely

n's pool. Find the area of the community center swimming pool. Please show work.
Mathematics
1 answer:
Anna007 [38]3 years ago
6 0

Answer:

  310.625 ft²

Step-by-step explanation:

Jocelyn's rectangular pool has an area that is the product of its length and width:

  area = L·W = (14.75 ft)(7.5 ft) = 110.625 ft

The community pool is 200 ft² larger, so its area is ...

  community pool area = 110.625 ft² +200 ft² = 310.625 ft²

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<span> </span>
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3 0
3 years ago
On a map, the distance between two towns is 3.4 inches. The map scale is 2 inches: 25 miles. What is the actual distance between
Mariulka [41]
For this question we can solve it by setting up a proportion:

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Now we can solve for x to find the total distance between the towns. Let's cross multiply and solve for x:

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So now we know that the total distance between the towns is 42.5 miles.
4 0
3 years ago
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