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Butoxors [25]
2 years ago
9

Round to the nearest tenth 0.12

Mathematics
2 answers:
Oksana_A [137]2 years ago
8 0
0.12 rounded to the nearest tenth is 0.1
Stells [14]2 years ago
8 0
0.12 rounded to the nearest tenth is 0.1

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One car costs $18,942.
oksian1 [2.3K]

Answer:

28,130

Step-by-step explanation:

18,942+9188=28,130

7 0
2 years ago
Read 2 more answers
The lateral area of a right cylinder which has a base diameter of 12 cm and a height of 8 cm is?
garik1379 [7]

Answer:

A = 301.59\ cm^2 or A=96\pi\ cm^2

Step-by-step explanation:

The lateral area of a cylinder is calculated by the following formula

A = 2\pi r * h.

Where r is the radius of the right cylinder and h is the height

In this case we know that the diameter d of the cylinder is

d=2r\\\\r=\frac{d}{2}\\\\r=\frac{12}{2}\\\\r=6\ cm

h=8\ cm

Therefore the lateral area is:

A = 2\pi*6 * 8.

A = 96\pi

A = 301.59\ cm^2

8 0
3 years ago
Read 2 more answers
Tom, Brad, Angela, and Mona went to a theater. In how many different ways can they sit on four adjacent seats in a line in the t
vladimir2022 [97]

Answer:

16

Step-by-step explanation:

4x4 = 16

5 0
3 years ago
Calculate the area of the shaded sector in the circle​
agasfer [191]

Answer:

Approximately, 6.283..

Step-by-step explanation:

First calculate the area of the whole circle

We have radius(r)=4 cm

Area of circle(a)=pir^2

=pi×(4)^2

=pi×16

=Approximately,50.265......

A cirlce has a total of 360 degrees

Therefore,we can conclude 360 degrees=50.265...

or,1 degree=50.265/360

1 degree=Approximately,0.139

Now,

Area for the shaded region = Area of 45 degree

=0.139×45=Approximately,6.283.....

Therefore,the area of the shaded region is approximately,6.283....

6 0
3 years ago
Two horses are ready to return to their barn after a long workout session at the track. The horses are at coordinates H(1,10) an
lana [24]
Distance between points \left(x_1,y_1\right) and \left( x_2,y_2 \right) is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

Distance from H to B:

[tex]d=\sqrt{(10-(-3))^2+(1-(-9))^2}=\sqrt{169+100}=\sqrt{269}d=\sqrt{(1-(-3))^2+(10-(-9))^2}=\sqrt{16+361}=\sqrt{376}[/tex] units.

Distance from Z to B:

d=\sqrt{(10-(-3))^2+(1-(-9))^2}=\sqrt{169+100}=\sqrt{269} units.

Horse Z is closer to the barn.

(The conversion to meters is not required; the question does not ask for actual distances, so "units" is OK.)
6 0
3 years ago
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