A vertical line that the graph of a function approaches but never intersects. The correct option is B.
<h3>When do we get vertical asymptote for a function?</h3>
Suppose that we have the function f(x) such that it is continuous for all input values < a or > a and have got the values of f(x) going to infinity or -ve infinity (from either side of x = a) as x goes near a, and is not defined at x = a, then at that point, there can be constructed a vertical line x = a and it will be called as vertical asymptote for f(x) at x = a
A vertical asymptote can be described as a vertical line that the graph of a function approaches but never intersects.
Hence, the correct option is B.
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Answer:
what are the numbers you wsnt to find? if you don't know then you've answeref your own question with this, well, question..!
U have a solid line...meaning there is an equal sign in the problem
u have a y int of -1 (the y int is where ur line crosses the y axis)
u have a slope of : 1
it is shaded below the line...so it is less then
so ur inequality is : y < = x - 1 <==
Answer:
The first 4 are correct and the last one is incorrect
Step-by-step explanation:
1. The diameter of the circle is 30.8 m ( Correct )
Radius = 15.4 so diameter is 2 times the radius which is 30.8 m
2. The circumference in terms of π is 30.8 π ( Correct )
Circumference = π × Diameter
Circumference = π × 30.8
Circumference = 30.8 π
3 . The circumference of the circle can be found using 2 × π × 15 . 4 ( Correct )
Circumference = π × Diameter
Circumference = π × 30.8
Circumference = 30.8 π
4 . The approximate circumference of the circle rounded to the nearest tenth is 96.7 m ( Correct )
Circumference = 30.8 π = 96.7610537306
5 . A little more than 6 diameters could be wrapped around the circle
( False )
Circumference = 96.7610537306
Diameter = 30 . 8
96.7610537306 ÷ 30 . 8 = 3.14
