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2 years ago

Find de product of 15 and 107

Mathematics

2 answers:

Andru [333]2 years ago

6 0

Answer:

$15 \times 107 = 1605$

Kryger [21]2 years ago

6 0

Answer:

1605

Step-by-step explanation:

1) In math, the Product is the answer to a Multiplication Problem

2) This means that we need to find the answer to 15 x 107

3) 15 x 107 means we are looking for what the answer will be if we add 15 to itself 107 times

4) An easy way to do this is plugging these numbers into a calculator.

15 x 107 = 1605

5) Another way to solve this is by expanding the numbers using a bracket

15 x 107

15 × ( 100 + 7)

15 x 100 + 15 x 7

1500 + 105

= 1605

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2 years ago

A vertical right circular cylindrical tank has height h=8 feet high and diameter d=6 feet. It is full of kerosene weighing 50 po

Mariana [72]

Answer:

The work done to pump all of the kerosene from the tank to an outlet is $W=45238.9\: J$

Step-by-step explanation:

The work is defined by:

$W=\int dFdx$ (1)

The force here will be the product between the volume and the kerosene weighing, so we have :

$dF=\pi R^{2}dy*50$

This force will be in-lbs.

Where R is the radius (3 feet)

Then using (1), we have:

$W=\int \pi R^{2}dy*50(8-y)$

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$W=\int_{0}^{8} \pi 3^{2}dy*50(8-y)$

$W=450\pi \int_{0}^{8}dy(8-y)$

$W=450\pi(\int_{0}^{8} 8dy-\int_{0}^{8} ydy)$

$W=450\pi(8y|_{0}^{8} -\frac{y^{2}}{2}|_{0}^{8})$

$W=450\pi(8*8 -\frac{8^{2}}{2})$

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Therefore, the work done to pump all of the kerosene from the tank to an outlet is $W=45238.9\: J$

I hope it helps you!

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2 years ago

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3 years ago

Read 2 more answers

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2 years ago

Answer correctly with good explanation. Please and thank you

Kaylis [27]

Answer:

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I hope this helped :))

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