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3 years ago

Oxygen in the simulation starts as a

Computers and Technology

1 answer:

Rufina [12.5K]3 years ago

6 0

Answer:

"continuous mode, which delivers constant oxygen-rich flow to the lung model."

Explanation:

https://www.google.com/search?q=Oxygen+in+the+simulation+starts+as+a&oq=Oxygen+in+the+simulation+starts+as+a&aqs=chrome..69i57j69i60.639j0j4&sourceid=chrome&ie=UTF-8

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Write a c program that reprints input so that no line is longer than 50 characters. Specifically, for lines less than or equal t

Alex73 [517]

Using the knowledge in computational language in C++ it is possible to write a code that reprints prints input so that no line is longer than 50 characters.

<h3>Writting the code:</h3>

#include<stdio.h>

int main(int argc, char** argv){

//creating pointer to read a file

FILE * fp;

char * line = NULL;

size_t len = 0;

ssize_t read;

int i=0;

//opening a file

fp = fopen(argv[1], "r");

//handling the error condition

if (fp == NULL){

printf("File not found..!!");

return 0;

}

int moreThan50 =0;

//reading a file line by line

while ((read = getline(&line, &len, fp)) != -1) {

i = 0;

if(read >= 50){

moreThan50++;

}

while(i < read){

if(line[i]!='\n'){

if(i%50 == 0){

printf("\n%c",line[i]);

}else{

printf("%c",line[i]);

}

i++;

}

printf("\nTotal lines over 50 chars: %d\n",moreThan50);

printf("Offending Lines: ");

for(i=1;i<=moreThan50;i++)

printf("%d, ",i);

fclose(fp);

return 0;

}

See more about C++ at brainly.com/question/19705654

#SPJ1

4 0

1 year ago

Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server

sattari [20]

Answer:

The smallest number of servers required is 3 servers

Explanation:

Given

$Reliability = 99.98\%$

$Individual Servers = 95\%$

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

$p = 95\%\\$

It should be noted that probabilities always add up to 1;

So,

$p + q = 1$ '

Subtract p from both sides

$p - p + q = 1 - p$

$q = 1 - p$

Substitute $p = 95\%\\$

$q = 1 - 95\%$

Convert % to fraction

$q = 1 - \frac{95}{100}$

Convert fraction to decimal

$q = 1 - 0.95$

$q = 0.05$

------------------------------------------------------------------------------------------------

To get an expression for one server

The probabilities of 1 servers having 99.98% reliability is as follows;

$p = 99.98\%$

Recall that probabilities always add up to 1;

So,

$p + q = 1$

Subtract q from both sides

$p + q - q = 1 - q$

$p = 1 - q$

So,

$p = 1 - q = 99.98\%$

$1 - q = 99.98\%$

Let the number of servers be represented with n

The above expression becomes

$1 - q^n = 99.98\%$

Convert percent to fraction

$1 - q^n = \frac{9998}{10000}$

Convert fraction to decimal

$1 - q^n = 0.9998$

Add $q^n$ to both sides

$1 - q^n + q^n= 0.9998 + q^n$

$1 = 0.9998 + q^n$

Subtract 0.9998 from both sides

$1 - 0.9998 = 0.9998 - 0.9998 + q^n$

$1 - 0.9998 = q^n$

$0.0002 = q^n$

Recall that $q = 0.05$

So, the expression becomes

$0.0002 = 0.05^n$

Take Log of both sides

$Log(0.0002) = Log(0.05^n)$

From laws of logarithm $Loga^b = bLoga$

So,

$Log(0.0002) = Log(0.05^n)$ becomes

$Log(0.0002) = nLog(0.05)$

Divide both sides by $Log0.05$

$\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}$

$\frac{Log(0.0002)}{Log(0.05)} = n$

$n = \frac{Log(0.0002)}{Log(0.05)}$

$n = \frac{-3.69897000434}{-1.30102999566}$

$n = 2.84310893421$

$n = 3 (Approximated)$

Hence, the smallest number of servers required is 3 servers

6 0

3 years ago

When recording data on a multiple-disk storage system, should we fill a complete disk surface before starting on another surface

Cerrena [4.2K]

The user needs to complete the entire disk surface first before starting another surface.

Explanation:

When you are using a multiple disk storage system to write the data the disk automatically writes the disk based on the algorithm for better efficiency and availability of the disk space.

hence when you are recording a data on a multiple disk storage system, it is recommended to fill the complete disk surface initially before you start the another surface to record the data.

4 0

3 years ago

How does form get its power natural gas

lana [24]

Answer:

because it does

Explanation:

7 0

3 years ago

Ipv6 includes a native information security framework (ipsec) that provides both data and control packets. true false

Galina-37 [17]

The statement that IPv6 includes a native information security framework (IPsec) that provides both data and control packets is false.
IPSec is a mandatory component for IPv6, and is used to natively protect IPv6 data as it is sent over the network,. and not control packets.
The IPv6 IPSec is a set of Internet standards that uses cryptographic security services to provide confidentiality ,data origin authentication and data integrity

5 0

3 years ago

Oxygen in the simulation starts as a​

Oxygen in the simulation starts as a