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Mandarinka [93]
2 years ago
11

10 Pts + Brainliest for best answer. Please answer quickly. Thanks!

Mathematics
2 answers:
abruzzese [7]2 years ago
7 0
Correct answer is C! Good luck!
Juliette [100K]2 years ago
5 0

m∠AOC = m∠AOB + m∠BOC

We have m∠AOC = 19°, m∠AOB = 4x - 15 and m∠BOC = 2x + 10. Substitute:

19 = (4x - 15) + (2x + 10)

19 = (4x + 2x) + (-15 + 10)

19 = 6x - 5          <em>add 5 to both sides</em>

24 = 6x       <em>divide both sides by 6</em>

4 = x

m∠BOC = 2x + 10 → m∠BOC = 2(4) + 10 = 8 + 10 = 18

m∠AOB = 4x - 15 → m∠AOB = 4(4) - 15 = 16 - 15 = 1

<h3>Answer: c. m∠BOC = 18°, m∠AOB = 1°</h3>
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A school dance committee has 14 volunteers. Each dance requires 3 volunteers at the door, 5 volunteers on the floor, and 6 float
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There are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned from 14 volunteers.

Given that a school dance committee has 14 volunteers and each dance requires 3 volunteers at the door, 5 volunteers on the floor and 6 on floaters.

We are required to find the number of ways in which the volunteers can be assigned.

Combinations means finding the ways in which the things can be choosed to make a new thing or to do something else.

nC_{r}=n!/r!(n-r)!

Number of ways in which the volunteers can be assigned is equal to the following:

Since 2 have not been assigned so left over volunteers are 14-2=12 volunteers.

Number of ways =14C_{12}

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