Quadrilateral EFGH was dilated by a scale factor of 2 from the center (1, 0) to create E'F'G'H'. Which characteristic of dilatio
ns compares segment F'H' to segment FH?
A). A segment that passes through the center of dilation in the pre-image continues to pass through the center of dilation in the image.
B). A segment that does not pass through the center of dilation in the pre-image is parallel to its corresponding segment in the image.
C). A segment in the image has the same length as its corresponding segment in the pre-image.
D). A segment that does not pass through the center of dilation in the pre-image is perpendicular to its corresponding segment in the image.
A). A segment that passes through the center of dilation in the pre-image continues to pass through the center of dilation in the image.
B). A segment that does not pass through the center of dilation in the pre-image is parallel to its corresponding segment in the image.
C). A segment in the image has the same length as its corresponding segment in the pre-image.
D). A segment that does not pass through the center of dilation in the pre-image is perpendicular to its corresponding segment in the image.
1 answer:
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Answer: The inequality solves to x ≥ 42
The graph is shown below
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Explanation:
We have some unknown number x, and we're dividing by 6 to form the fraction x/6. That result is 7 or larger which means we write x/6 ≥ 7
To solve for x, we undo the division. We'll multiply both sides by 6. That's how we get to x ≥ 42
The graph will involve a number line. Plot a closed filled in circle at 42 on the number line. Shade to the right. This visually represents any number that is 42 or larger. The endpoint 42 itself is included in the solution set.
Side note: We would use an open circle if we didn't have the "or equal to" portion for the inequality sign.
