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ArbitrLikvidat [17]
3 years ago
9

Tyler and Ben plan on taking a road trip to Yellowstone National Park. Tyler's car currently has 45,000 miles on it. They plan o

n traveling, on avergae, 60 mph. Define the variables. Write an equation that represents the car's mileage according to the number of hours that they travel on the trip. Use the equation to find the odometer reading after 13 hours of travel. Show your work.
Mathematics
1 answer:
Nastasia [14]3 years ago
7 0
X = number of hours traveled
Y = Total miles on the car

Y = 60x +45 000

for 13 hours

Y = 60(13) + 45 000
Y = 45 780


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16d=10<br> What’s the answer??<br> I need it quick plz
Elanso [62]

Answer: d = 5/8

Step-by-step explanation:

first, you divide both sides.

16d / 16 = 10 / 16

then, you divide and rewrite.

d = 16/10

then, reduce the fraction.

d = 5/8

4 0
3 years ago
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WILL MARK BRAINLIEST
pentagon [3]
We know, nickel = 5 cents
& 1 dime = 10 cents,

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Total, money = 1000 cents ($10)

& You need to shade the area below the line for positive values of x and y.

By collecting all the datas from above, option A is your answer.

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Consider the vectors u &lt;-4,7&gt; and v= &lt;11,-6&gt;
coldgirl [10]

Answer:

u + v = <7 , 1>

║u + v║ ≅ 7

Step-by-step explanation:

* Lets explain how to solve the problem

- We can add two vector by adding their parts

∵ The vector u is <-4 , 7>

∵ The vector v is <11, -6>

∴ The sum of u and v = <-4 , 7> + <11 , -6>

∴ u + v = <-4 + 11 , 7 + -6> = <7 , 1>

∴ The sum u and v is <7 , 1>

* u + v = <7 , 1>

- The magnitude of the resultant vector = √(x² + y²)

∵ x = 7 and y = 1

∵ ║u + v║ means the magnitude of the sum

∴ The magnitude of the resultant vector = √(7² + 1²)

∴ The magnitude of the resultant vector = √(49 + 1) = √50

∴ The magnitude of the resultant vector = √50 = 7.071

* ║u + v║ ≅ 7

4 0
4 years ago
Can someone help me?
motikmotik

Answer:

Segment DE is parallel to segment BC.

Step-by-step explanation:

Use the side splitter theorem.

Answer: Segment DE is parallel to segment BC.

8 0
3 years ago
4. One in four people in the US owns individual stocks. You randomly select 12 people and ask them if they own individual stocks
BartSMP [9]

Answer:

a. The mean is 3, the variance is 2.25 and the standard deviation is 1.5.

b. 0.0401 = 4.01% probability that the number of people who own individual stocks is exactly six.

c. 0.1584 = 15.84% probability that the number of people who say they own individual stocks is at least two.

d. 0.3907 = 39.07% probability that the number of people who say they own individual stocks is at most two

e. Both cases include one common outcome, that is, 2 people owning stocks, so the events are not mutually exclusive.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they own stocks, or they do not. The probability of a person owning stocks is independent of any other person, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

One in four people in the US owns individual stocks.

This means that p = \frac{1}{4} = 0.25

You randomly select 12 people and ask them if they own individual stocks.

This means that n = 12

a. Find the mean, variance, and standard deviation of the resulting probability distribution.

The mean of the binomial distribution is:

E(X) = np

So

E(X) = 12(0.25) = 3

The variance is:

V(X) = np(1-p)

So

V(X) = 12(0.25)(0.75) = 2.25

Standard deviation is the square root of the variance, so:

\sqrt{V(X)} = \sqrt{2.25} = 1.5

The mean is 3, the variance is 2.25 and the standard deviation is 1.5.

b. Find the probability that the number of people who own individual stocks is exactly six.

This is P(X = 6). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{12,6}.(0.25)^{6}.(0.75)^{6} = 0.0401

0.0401 = 4.01% probability that the number of people who own individual stocks is exactly six.

c. Find probability that the number of people who say they own individual stocks is at least two.

This is:

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.25)^{0}.(0.75)^{12} = 0.0317

P(X = 1) = C_{12,1}.(0.25)^{1}.(0.75)^{11} = 0.1267

P(X < 2) = P(X = 0) + P(X = 1) = 0.0317 + 0.1267 = 0.1584

0.1584 = 15.84% probability that the number of people who say they own individual stocks is at least two.

d. Find the probability that the number of people who say they own individual stocks is at most two.

This is:

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.25)^{0}.(0.75)^{12} = 0.0317

P(X = 1) = C_{12,1}.(0.25)^{1}.(0.75)^{11} = 0.1267

P(X = 2) = C_{12,2}.(0.25)^{2}.(0.75)^{10} = 0.2323

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0317 + 0.1267 + 0.2323 = 0.3907

0.3907 = 39.07% probability that the number of people who say they own individual stocks is at most two.

e. Are the events in part c. and in part d. mutually exclusive

Both cases include one common outcome, that is, 2 people owning stocks, so the events are not mutually exclusive.

5 0
3 years ago
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