Y - (-1/2) = 3(x - 2)
y + 1/2 = 3(x - 2)
The equation of a straight line in "standard form" resembles Ax + By + C = 0.
Starting with y − 3 = 1/3(x − 6) (which is the equation of a line in point-slope form), remove the fractional coefficient 1/3 by multiplying both sides of this equation by 3:
3y - 9 = x - 6.
We want all terms except for 0 to appear on one side of this equation. Subtract 3y from both sides, obtaining:
-9 = 1x - 3y - 6
Finally, add 9 to both sides, obtaining:
0 = 1x - 3y + 3
This result has the form Ax + By + C = 0, and is thus in standard form.
Answer:
C
Step-by-step explanation:
In quadrant 2 (second quadrant) the X is negative and the Y is positive.
So C is the answer.
