small frames ($8): s
large frames ($15): L
Cost: 8s + 15L = 239 ⇒ 1(8s + 15L = 239) ⇒ 8s + 15L = 239
Quantity: s + L = 22 ⇒ -8( s + L = 22) ⇒ <u> -8s -8 L = -176 </u>
7L = 63
L = 9
Quantity: s + L = 22 ⇒ s + (9) = 22 ⇒ s = 13
Answer: 13 small frames, 9 Large frames
To reproduce. But if this is suicidal type there are people here for you
Answer:
negitive 8
Step-by-step explanation:
you would have to use a negitive because 12 os higher than 5 and it has to be over 7 or negitive 7
Step 1: 0.416 = 416⁄1000
Step 2: Simplify 416⁄1000 = 52⁄125
LW < = A (thats less then or equal to)
W = x
L = x + 18
A = 175
x(x + 18) < = 175
x^2 + 18x - 175 < = 0
(x + 25)(x - 7) < = 0
x + 25 < = 0
x < = -25.....extraneous solution...not ur answer
x - 7 < = 0
x < = 7 <==
so anything less then or equal to 7 can be a possible width
