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Varvara68 [4.7K]
3 years ago
10

The sum of a rational number and an irrational number?

Mathematics
1 answer:
Semenov [28]3 years ago
3 0

Answer:

Is irrational

Step-by-step explanation:

Let r be a rational number, and i be an irrational number. If their sum were rational, say q, then we'd have

r+i=q \iff i=q-r

but q-r is the difference between two rational numbers, and thus a rational number. But it also equals i, which is irrational by hypothesis. Since we have a contradiction, we conclude that the sum of a rational and an irrational can't be rational.

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HW 7.4/7.5 help mhhhh
Hatshy [7]

Answer:

1. LI=18

2. x=10

3. Yes (Y)

4. Yes (Y)

5. x=15

6. x=18

7. x=8

8. x=6

   y=6.5

Step-by-step explanation:

1. LI/JL=KH/JK

Replacing the given values:

LI/6=21/7

Dividing on the right side of the equation:

LI/6=3

Solving for LI: Multiplying both sides of the equation by 6:

6(LI/6)=6(3)

LI=18


2.TV/VS=RU/US

Replacing the given values:

x/17.5=8/14

Simplifying the fraction on the right side of the equation: Dividing numerator and denominator by 2:

x/17.5=(8/2) / (14/2)

x/17.5=4/7

Solving for x: Multiplying both sides of the equation by 17.5:

17.5(x/17.5)=17.5(4/7)=(17.5/1)(4/7)

Multiplying:

x=(17.5 x 4) / (1 x 7)

x=70/7

Dividing:

x=10


3. BC is parallel to DE if AD/DB is equal to AE/EC:

AD/DB=15/12=(15/3) / (12/3)→AD/DB=5/4

AE/EC=10/8=(10/2) / (8/2)→AE/EC=5/4

Like AD/DB=5/4=AE/EC → BC is parallel to DE


4. BC is parallel to DE if AD/DB is equal to AE/EC:

AD/DB= 2DB / DB→AD/DB=2

AE/EC=30 / (AC-AE)=30 / (45-30)=30/15→AE/EC=2

Like AD/DB=2=AE/EC → BC is parallel to DE


5. If JH is a midsegment of triangle KLM:

x=(1/2)(30)

x=15


6. If JH is a midsegment of triangle KLM:

x=2(9)

x=18


7. If JH is a midsegment of triangle KLM: x=8


8. 2x+1=x+7

Solving for x. Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

2x+1-x=x+7-x

Subtracting:

x+1=7

Subtracting 1 both sides of the equation:

x+1-1=7-1

Subtracting:

x=6

2x+1=2(6)+1=12+1→2x+1=13

x+7=6+7→x+7=13


(3y-8)/(y+5)=(2x+1)/(x+7)

(3y-8)/(y+5)=13/13

(3y-8)/(y+5)=1

3y-8=y+5

Solving for y. Grouping the y's on the left side of the equation: Subtracting y both sides of the equation:

3y-8-y=y+5-y

Subtracting:

2y-8=5

Adding 8 both sides of the equation:

2y-8+8=5+8

Subtracting:

2y=13

Dividing both sides of the equation by 2:

2y/2=13/2

Dividing:

y=6.5



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3 years ago
I also bought $7$ different postcards. How many ways can I send the postcards to my $3$ friends, so that each friend gets at lea
harina [27]
Bruh how’s it gonna tell me incorrect answer when it was right
5 0
3 years ago
A light bulb consumes 2400 watt-hours per day. How long does it take to consume 13800 watt-hours?
olga55 [171]
It will take about 5.75 days. basicly 5 days and 18 hours.
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3 years ago
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Si Martha retira de su cuenta el 10% para los transportes del mes. ¿Cuál es el nuevo saldo de la cuenta?
notsponge [240]

Respuesta:

0,9 veces

Explicación paso a paso:

Deje que la cantidad en la cuenta de Martha se denote como x, que es la cantidad en la cuenta = x

Porcentaje retirado para transporte = 10%

El porcentaje total siempre será del 100%

Por lo tanto, si se retira el 10%, entonces; el porcentaje restante es:

Porcentaje total: porcentaje gastado en transporte

(100% - 10%) * monto en cuenta

90% * x = 0,9 * x = 0,9x

Saldo de cuenta nueva = 0.9x

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Help please I need answer asap BRAINLIEST
KATRIN_1 [288]

Answer:

it should be the same line, if they are completely equal in miles and cost

7 0
3 years ago
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