The answer to your question is 50%
Answer:

Step-by-step explanation:
-5/2 × (3x + 4) < 6x - 3x
-15/2x - 10 < 3x
-15x - 20 < 6x
-15x - 6x < 20
-21x < 20
<u>x</u><u> </u><u>></u><u> </u><u>-</u><u>2</u><u>0</u><u>/</u><u>2</u><u>1</u>
Answer:
10
Step-by-step explanation:
let the lengths of sides=x (each)
x²+x²=(10√2)²
2x²=100×2
x²=100
x=√100=10
Answer:
a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Step-by-step explanation:
I am going to solve this question treating these events as Venn probabilities.
I am going to say that:
Event A: Person has type A blood.
Event B: Person has Rh- factor.
43% of people have type O blood
This means that 
15% of people have Rh- factor
This means that 
52% of people have type O or Rh- factor.
This means that 
a. Find the probability that a person has both type O blood and the Rh- factor.
This is

With what we have

0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b. Find the probability that a person does NOT have both type O blood and the Rh- factor.
1 - 0.06 = 0.94
0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.