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soldi70 [24.7K]
2 years ago
9

If you know the answer to these plz answer.

Mathematics
1 answer:
kondaur [170]2 years ago
7 0

Answer:


Step-by-step explanation:  

You can readily see from the diagram, above, that the side length of the middle cube will be between 3 and 4.  You want to determine to the nearest hundredth what value between 3 and 4 represents the side length of the cube whose volume is 45 units^3.

Please note:  the middle cube has been mislabeled.  Instead of volume = 30 units^3, the volume should be 45 units^3.

Here's the procedure:

Guess an appropriate s value.  Let's try s = side length = 3.5

Cube this:  (3.5 units)^3 = 42.875.  Too small.  Choose a larger possible side length, such as 3.7:  3.7^3 = 50.653.  Too large.

Try s = 3.6:  3.6^3 = 46.66.  Too large.

Choose a smaller s, one between 3.5 and 3.6:  3.55^3 = 44.73.  This is the best estimate yet for s.  Continue this work just a little further.  Try s = 3.57.  Cube it.  How close is the result to 45 cubic units?


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Step-by-step explanation:

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a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.

b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.

Step-by-step explanation:

I am going to solve this question treating these events as Venn probabilities.

I am going to say that:

Event A: Person has type A blood.

Event B: Person has Rh- factor.

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This means that P(A) = 0.43

15% of people have Rh- factor

This means that P(B) = 0.15

52% of people have type O or Rh- factor.

This means that P(A \cup B) = 0.52

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This is

P(A \cap B) = P(A) + P(B) - P(A \cup B)

With what we have

P(A \cap B) = 0.43 + 0.15 - 0.52 = 0.06

0.06 = 6% probability that a person has both type O blood and the Rh- factor.

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1 - 0.06 = 0.94

0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.

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