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3 years ago

On a coordinate plane, a polygon has points (negative 3, 4), (3, 4), (3, negative 3), (negative 3, negative 2).

Mathematics

2 answers:

alexandr1967 [171]3 years ago

6 0

Answer:

(-3,-2)

(-3,4)

(3,4)

(3,-3)

Step-by-step explanation:

stellarik [79]3 years ago

6 0

Answer:

cant see nun mind showing it

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Please help right now!!!!! Solve the system of equations below. x + y = 7 2x + 3y = 16

motikmotik

Answer:

$x=5$ and $y=2$ .

Step-by-step explanation:

We have been given a system of equations. We are asked to solve our given system.

$x+y=7...(1)$

$2x+3y=16...(2)$

From equation (1), we will get:

$x=7-y$

Upon substituting this value in equation (2), we will get:

$2(7-y)+3y=16$

$14-2y+3y=16$

$14+y=16$

$14-14+y=16-14$

$y=2$

Now, we will substitute $y=2$ in equation (1).

$x+2=7$

$x+2-2=7-2$

$x=5$

Therefore, the point $(5,2)$ is solution for our given equation.

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3 years ago

Work out the total number of mobile phones sold in the 3 years

svetlana [45]

Answer: your wuestion isn’t specific enough.

Step-by-step explanation:

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3 years ago

A certain math textbook is 3/4 of an inch thick. how many of these books will fit on a shelf that is 3 feet wide

Advocard [28]

48 books will fit on this shelf.

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3 years ago

What is the slope-intercept form equation of the line that passes through (2, 4) and (4, 10)? (5 points) a y = −3x − 2 b y = −3x

Nadya [2.5K]

Answer:

Step-by-step explanation:

6 0

3 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

kompoz [17]

$f_{X,Y,Z}(x,y,z)=\begin{cases}Ce^{-(0.5x+0.2y+0.1z)}&\text{for }x\ge0,y\ge0,z\ge0\\0&\text{otherwise}\end{cases}$

is a proper joint density function if, over its support, $f$ is non-negative and the integral of $f$ is 1. The first condition is easily met as long as $C\ge0$ . To meet the second condition, we require

$\displaystyle\int_0^\infty\int_0^\infty\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=100C=1\implies \boxed{C=0.01}$

b. Find the marginal joint density of $X$ and $Y$ by integrating the joint density with respect to $z$ :

$f_{X,Y}(x,y)=\displaystyle\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dz=0.01e^{-(0.5x+0.2y)}\int_0^\infty e^{-0.1z}\,\mathrm dz$

$\implies f_{X,Y}(x,y)=\begin{cases}0.1e^{-(0.5x+0.2y)}&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}$

Then

$\displaystyle P(X\le1.375,Y\le1.5)=\int_0^{1.5}\int_0^{1.375}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy$

$\approx\boxed{0.12886}$

c. This probability can be found by simply integrating the joint density:

$\displaystyle P(X\le1.375,Y\le1.5,Z\le1)=\int_0^1\int_0^{1.5}\int_0^{1.375}f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz$

$\approx\boxed{0.012262}$

7 0

3 years ago