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Lady bird [3.3K]
3 years ago
15

How to use the results of part (b) and appropriate computation formulas to compute the sample variances s2 and sample standard d

eviation s.

Mathematics
1 answer:
anygoal [31]3 years ago
7 0
s^2=\displaystyle\sum\frac{(x-\bar x)^2}{n-1}=\frac1{n-1}\sum(x^2-2x\bar x+{\bar x}^2)=\frac{\displaystyle\sum x^2-2\bar x\sum x+{\bar x}^2}{n-1}

where \bar x=22 is the mean. Since

\sum x^2=2568
\sum x=110

you have variance

s^2=\dfrac{2568-2(22)(110)+22^2}{5-1}=37

and so the standard deiviation is

s=\sqrt{37}\approx6.083
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HELP IDENTIFY THE TERMS AND LIKE TERMSS
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Answer:

The terms are:

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The like terms are:

-9x^{2},12x^{2}

3 0
2 years ago
How much of a radioactive kind of thorium will be left after 14,680 years if you start with
babymother [125]

Answer:

8978 grams

Step-by-step explanation:

The equation to find the half-life is:

N(t)= N_{0}e^{-kt}

N(t) = amount after the time <em>t</em>

N_{0} = initial amount of substance

t = time

It is known that after a half-life there will be twice less of a substance than what it intially was. So, we can get a simplified equation that looks like this, in terms of half-lives.

N(t)= N_{0}e^{-\frac{ln(\frac{1}{2}) }{t_{h} } t} or more simply N(t)= N_{0}(\frac{1}{2})^{\frac{1}{t_{h} } }

t_{h} = time of the half-life

We know that N_{0} = 35,912, t = 14,680, and t_{h}=7,340

Plug these into the equation:

N(t) = 35912(\frac{1}{2})^{\frac{14680}{7340} }

Using a calculator we get:

N(t) = 8978

Therefore, after 14,680 years 8,978 grams of thorium will be left.

Hope this helps!! Ask questions if you need!!

8 0
2 years ago
Please help me!
Mandarinka [93]

Answer:

its c

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The graph of a function f(x) passes through the following points:
Alex

The function is f(x) = -2x² + 2 if the function f(x) passes through the following points:(0,2), (1, 0), (-1,0)

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have:

The graph of a function f(x) passes through the following points: (0,2), (1, 0), (-1,0)

Let

f(x) = ax² + bx + c

Plug x = 0, and y = 2

c = 2 ...(1)

Plug x = 1 and y = 0

a + b + c = 0 ..(2)

Plug x = -1 and y = 0

a - b + c = 0  ...(3)

After solving (1), (2), and (3)

a = -2

b = 0

c = 2

f(x) = -2x² + 2

Thus, the function is f(x) = -2x² + 2 if the function f(x) passes through the following points:(0,2), (1, 0), (-1,0)

Learn more about the function here:

brainly.com/question/5245372

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5 0
2 years ago
Simplify:<br><br> 3-2<br> what is this awnser
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Answer:

It is ................................................................. 1

Step-by-step explanation:

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