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miskamm [114]
3 years ago
5

HELP

Mathematics
1 answer:
Sveta_85 [38]3 years ago
3 0

Answer:

100+15p < 25p

Step-by-step explanation:

Note that

> means greater than

< means less than

≥ means greater than or equal to  

≤ less than or equal to  

total cost of travelling = cost to rent a bus + total cost of ticket for p persons

100 + 15p

they want to spend less than an average cost of 25 per p people

they want to spend less than 25p

since they dont want to spend less than 25p, < would be used

100+15p < 25p

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Use pythagoras theorem to find height. you get, h=4. so volume ,v= \frac{\pi r^{2}h}{3}

u get,v=\pi *3*4= 12 \pi
6 0
3 years ago
The distance between the points (4, 5) and (2, 2)
Morgarella [4.7K]

Answer:

(2,3)

Step-by-step explanation:

6 0
2 years ago
Solve the equation<br> (x-3)^3-( x - 1 )^3 + 7x^2 = 7(3x - 4 )
Yakvenalex [24]

Answer:

x= -1 or x = -2

Step-by-step explanation:

Your equation:

(x−3)^3−(x−1)^3+7x^2=7(3x−4)

Step 1: Simplify both sides of the equation.

x^2+24x−26=21x−28

Step 2: Subtract 21x-28 from both sides.

x^2+24x−26−(21x−28)=21x−28−(21x−28)

x^2+3x+2=0

Step 3: Factor left side of equation.

(x+1)(x+2)=0

Step 4: Set factors equal to zero.

x+1=0 or x+2=0

which equals to x=−1 or x=−2

8 0
2 years ago
Please help this is important for me.
Anit [1.1K]
<h3>Answer: point Q is located at (-1, 1)</h3>

=================================================

Explanation:

Check out the diagram below.

Plot R(-3,7) and T(3,-11) on the same xy grid.

Draw a vertical line through R and a horizontal line through T. A right triangle forms. At the intersection point is point S(-3,-11)

----------------------

Now measure the distance from point S to point T. You can count out the spaces or subtract the x coordinates and use absolute value.

|x1-x2| = |-3-3| = |-6| = 6

From point S to point T is 6 units.

We want to subdivide this horizontal length in the ratio 1:2

What this means is that we want to plot a point U somewhere such that SU:UT = 1:2

In other words,

SU = x

UT = 2x

SU+UT = ST

x+2x = 6

3x = 6

x = 6/3

x = 2

So we must move 2 spaces to the right from point S to get to U(-1,-11)

Going from point U(-1,-11) to T(3,-11) is 4 spaces

We have SU:UT = 2:4 = 1:2 to help confirm we have the correct location for point U

From point U, we then move straight up to the line segment RT

We'll land on Q(-1,1)

----------------------

Another way to find the y coordinate of point Q is to subdivide the segment RS into the ratio 1:2 similar to how we divided ST up

Segment RS is 18 units long since we go from y = 7 to y = -11 when going from R to S.

If V was on segment RS such that

RV:VS = 1:2

and RV = y

then

RV+VS = RS

y+2y = 18

3y = 18

y = 6

RV = y = 6

VS = 2y = 2*6 = 12

So you'll move 6 units down from y = 7 to land on y = 1 (when going from the y coordinate of R to the y coordinate of Q)

3 0
3 years ago
PLEASE PLEASE HELP THE OTHER BRAINLY ANSWERS WERE WRONG IM BEING TIMED
barxatty [35]

Answer:

A table?

Step-by-step explanation:

fingers crossed this is right

7 0
3 years ago
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