Center : Mean Before the introduction of the new course, center = average(121,134,106,93,149,130,119,128) = 122.5 After the introduction of the new course, center = average(121,134,106,93,149,130,119,128,45) = 113.9 The center has moved to the left (if plotted in a graph) because of the low intake for the new course. Spread before introduction of the new course : Arrange the numbers in ascending order: (93, 106,119, 121), (128, 130,134, 149) Q1=median(93,106,119,121) = 112.5 Q3=median(128,130,134,149) = 132 Spread = Interquartile range = Q3-Q1 = 19.5 After addition of the new course,
(45,93, 106,119,) 121, (128, 130,134, 149)
Q1=median(45,93,106,119)=99.5
Q3=median (128, 130,134, 149)= 132
Spread = Interquartile range = 132-99.5 =32.5
We see that the spread has increased after the addition of the new course.
Answer:
An odd number times an even number is always even
e.g 2 × 3 = 6
4 × 5 = 20
adding 1 to an even number makes it odd
6 + 1 = 7
20 + 1 = 21
hope this helps...
Answer:
1) 4 wild cards
2) 51.5 bones, rounded up to 52 bones
3) 72 blue balls.
Step-by-step explanation:
1) For every 18 cards in the game, there is 1 wild card.
For 72 cards in the game, there are 72/18 * 1 = 4 wild cards.
2) For every 4 bones, 1 is in the feet.
For 206 bones, 206/4 * 1 = 51.5 are in the feet. Though, you can't have half a bone, so I'd round it up to 52 bones in the feet.
3) For every 6 + 5 = 11 balls, there are 6 blue and 5 red.
For every 132 balls, there are 132/11 * 6 = 72 blue and 132/11 * 5 = 60 red.
There are 72 blue balls.
Answer:
x = 13
Step-by-step explanation:
Inscribed Angle = 1/2 Intercepted Arc
30 = 1/2 (5x-5)
Multiply each side by 2
2*30 = 2* 1/2 ( 5x-5)
60 = 5x-5
Add 5 to each side
60+5 = 5x-5+5
65 = 5x
Divide each side by 5
65/5 = 5x/5
13 = x
Answer:
4 1/3
Step-by-step explanation:
Hope this helps :)
