4^y=x
log(4^y)=logx
y*log4=logx
y=logx/log4
so, this is a log function, so it is not B,
vertical asymptote for this function is 0, so it did not move right or left (the graph will be look like log x), correct answer is C
Answer:
Center: (2, -11)
Radius: 10
Step-by-step explanation:
(x - 2)² + (y + 11)² = 100
(x - h)² + (y - k)² = r²
-------------------------------
x - 2 = 0
+2 +2
x = 2
------------
y + 11 = 0
-11 -11
y = -11
------------------------------
r² = 100
r = √100
r = 10
----------------------------
Center: (h, k)
Radius: r
-------------------------------
Center: (2, -11)
Radius: 10
I hope this helps!
Complete the comparison: 5+4=? =9
Answer:
The angle must be at 3.81°
Step-by-step explanation:
The horizontal distance of the shooting range is 60 yards
The height of the target is 12ft.
We'll have to convert the value of the height from ft to yards.
1 yards = 3 foot
X yards = 12ft
X = 4yards.
The height of the target is 4 yards.
Now, to find the angle at which the shooter makes with the zenith of the target(height), we'll have to use use SOHCAHTOA
To know which of the rules we'll follow, a pictorial illustration of the values will help
(See attached document for better illustration).
From the diagram, we can see we have values at both opposite and adjacent.
Opposite = 4
Adjacent = 60
Hence we can use Tanθ = opposite/ adjacent
Tanθ = 4 / 60
Tanθ = 0.067
θ = Tan⁻0.067
θ = 3.81°
The angle at which the rifle must be set to hit the target is 3.81°
2y=29+3
2y=32
Y=32/2
Y=16
Hope that is right