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IRISSAK [1]
2 years ago
14

Classify computer based on signal

Computers and Technology
1 answer:
Karolina [17]2 years ago
3 0

Answer:

Computers use analog and digital signals in order to process raw data into useful information. Whereas the former is fast at processing results, the latter gives the most accurate information. Somewhere in between is hybrid processing, which is meant to combine the advantages of the aforementioned technologies.

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Write a program that prompts the user to enter positive integers (as many as the user enters) from standard input and prints out
julia-pushkina [17]

Answer:

Here is the JAVA program that prompts the user to enter positive integers from standard input and prints out the maximum and minimum values:

import java.util.*;

public class Ex0603 {

   public static void main(String[] args) { //start of main function

   Scanner in = new Scanner(System.in); //creates Scanner class object to take input from user

   int minimum = 0; //stores the minimum of the integers

   int maximum = 0; //stores the minimum of the integers

   int num; //stores the positive integer values

   System.out.println("enter a positive integer: ");//prompts user to enter a positive integer

   num = in.nextInt();//scans and reads the input integer value from user

   minimum = num;  //assigns value of num to minimum

   while(true) {//while loop keeps prompting user to enter a positive integer

       System.out.println("enter a positive integer: ");//prompts user to enter a positive integer

       num = in.nextInt();//scans and reads the input integer value from user

       if(num <=0)//if the user inputs a negative integer or 0

           break; //breaks the loop

       if (num > maximum) {//if the value of positive integer is greater than the maximum of value

           maximum = num; } //assigns that maximum value of num to maximum variable

       if (num < minimum) {//if the value of positive integer is less than the minimum of value

           minimum = num; //assigns that minimum value of num to minimum       }    }            

   System.out.println("The maximum integer is : " + maximum); //displays the maximum of the positive integers

   System.out.println("The minimum integer is : " + minimum); }}   //displays the minimum of the positive integers

Explanation:

Here is the JAVA program that that prompts the user to enter an integer N, then reads N double values, and prints their mean (average value) and sample standard deviation:

import java.util.*;  

public class Ex0603 {  

public static void main(String[] args) { //start of main function

Scanner in = new Scanner(System.in);  //creates Scanner class object to take input from user

double integer= 0;  //to store the number of input values

double sum = 0;  //to store the sum of input numbers

double mean = 0;  //to store the average of numbers

double sd = 0;  //to store the standard deviation result

double variance = 0;  //to store the variance result

double sumSquare = 0;  //to store the sum of (num-mean)^2

int n = 0;  //to store the sample size N

   System.out.println("Enter an integer: ");  //prompts user to enter an integer that is how many elements user wants to input

   integer = in.nextInt();  //reads the value of integer from user

   double size=integer; // declares a double type variable and assigns value of int type variable integer to this double type variable size

   int i=0;  //used to point each element of the num array

   double num[] = new double[(int)size];  //declares an array to hold the numbers input by user

   while(integer>0){  //loop executes until value of integer is greater than 0

   System.out.println("Enter a number: "); // prompts to enter a number

   num[i] = in.nextDouble(); //reads double values

   sum += num[i];  //adds the values stored in num array

   i++;  //increments i to point to the next element in num array

   n++;  //increments n to count the total number of elements

  integer--; //decrements integer value at each iteration

   mean = sum / n;    }  //compute the average of values

   i=0;  

    while(size>0){  //loop executes until value of size exceeds 0

       sumSquare += Math.pow(num[i]-mean,2); //takes the sum of square difference between each element of num array and value of mean

       i++; //increments i

      size--;   }  //decrements size

variance = sumSquare / (n-1);  //compute variance by dividing the result of sum of the squares of their differences from the mean by n-1

   sd = Math.sqrt(variance);  //computes standard deviation by using sqrt function which takes the sqrt of the result of variance computed above

System.out.println("Average value is: " + mean+ " and the standard deviation is " + String. format("%.2f", sd));   }} //displays the average of numbers stored in mean variable and value of standard deviation is displayed up to 2 decimal places

Screenshots of both programs and their outputs is attached.

7 0
3 years ago
Which is a disadvantage of pie charts?
anzhelika [568]
While the reader of a pie chart can clearly see which categories dominate, it can be difficult to see categories that occupy only a small percentage of the chart. This problem becomes worse if there are many small categories in the chart. Labeling the categories can also be difficult.
6 0
3 years ago
Suppose a switch is built using a computer work station and that it can forward packets at a rate of 500,000 packets per second,
Marina86 [1]

Answer:

When the transmission exceeds 667 packets

Explanation:

In computer networking, a packet is a chunk of data transmitted across the network. The packet size of an Ethernet network is 1.5kilobytes, while the packet size of an IP packet payload is 64 kilobytes.

A switch is a physical network device that connects nodes or workstations while communicating the packets (or frames). The I/O bus size bandwidth is 1Gbps which allows approximately 667 packets. Once this packet size is crossed, the bus becomes a limiting factor or bottle neck.

3 0
3 years ago
Identify the different groups of keys on a keyboard
kifflom [539]

Answer:alphabetic keys, numeric keys, function keys and special keys.

Explanation:

6 0
3 years ago
A student is conducting an experiment in which he adds an inhibitor to an enzyme-catalyzed reaction that contains alkaline phosp
Zigmanuir [339]

Answer:

competitive

Explanation:

An inhibitor is a substance that hinders the action of an enzyme. An inhibitor may be competitive or non competitive.

A competitive inhibitor is an inhibitor that is very similar to the substrate hence it binds to the enzyme instead of the substrate. A noncompetitive inhibitor binds to a site that is different from the active site. This site is called an allosteric site.

If we look at the experiment described in the question, the reaction rate decreases upon addition of the inhibitor. This effect is reversed by adding a large quantity of substrate.

The implication of this observation is that the enzyme and the inhibitor compete for the active site on the substrate.

Hence the inhibitor is a competitive inhibitor.

7 0
2 years ago
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