Answer:
Area=1.5(1.5)=2.25m^2
Force of gravity=10N
\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}\end{gathered}
⟼Pressure=
Area
Force
\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{10}{2.25}\end{gathered}
⟼Pressure=
2.25
10
\begin{gathered}\\ \sf\longmapsto Pressure=4.4Pa\end{gathered}
⟼Pressure=4.4Pa
Explanation:
It is known that relation between velocity and height is as follows.
v = ![\sqrt{2gh}](https://tex.z-dn.net/?f=%5Csqrt%7B2gh%7D)
where, g = acceleration due to gravity = 9.8 ![m/s^{2}](https://tex.z-dn.net/?f=m%2Fs%5E%7B2%7D)
h = height = 0.2 m
Therefore, velocity is calculated as follows.
v = ![\sqrt{2gh}](https://tex.z-dn.net/?f=%5Csqrt%7B2gh%7D)
= ![\sqrt{2 \times 9.8 \times 0.2}](https://tex.z-dn.net/?f=%5Csqrt%7B2%20%5Ctimes%209.8%20%5Ctimes%200.2%7D)
= 3.92 m/s
Also,
![m_{people}v_{people} = m_{earth}v_{earth}](https://tex.z-dn.net/?f=m_%7Bpeople%7Dv_%7Bpeople%7D%20%3D%20m_%7Bearth%7Dv_%7Bearth%7D)
![v_{earth} = \frac{m_{people}v_{people}}{m_{earth}}](https://tex.z-dn.net/?f=v_%7Bearth%7D%20%3D%20%5Cfrac%7Bm_%7Bpeople%7Dv_%7Bpeople%7D%7D%7Bm_%7Bearth%7D%7D)
Putting the given values into the above formula as follows.
![v_{earth} = \frac{m_{people}v_{people}}{m_{earth}}](https://tex.z-dn.net/?f=v_%7Bearth%7D%20%3D%20%5Cfrac%7Bm_%7Bpeople%7Dv_%7Bpeople%7D%7D%7Bm_%7Bearth%7D%7D)
= ![\frac{6 \times 10^{9} \times 74 kg/person}{6 \times 10^{24} kg}](https://tex.z-dn.net/?f=%5Cfrac%7B6%20%5Ctimes%2010%5E%7B9%7D%20%5Ctimes%2074%20kg%2Fperson%7D%7B6%20%5Ctimes%2010%5E%7B24%7D%20kg%7D)
= ![\frac{444 \times 10^{9}}{6 \times 10^{24}}](https://tex.z-dn.net/?f=%5Cfrac%7B444%20%5Ctimes%2010%5E%7B9%7D%7D%7B6%20%5Ctimes%2010%5E%7B24%7D%7D)
=
m/s
or, =
m/s
Thus, we can conclude that recoil speed of the Earth is
m/s.
Answer:
20% of the human body float above the surface in the dead sea.
Explanation:
Given data,
The human density after inhaling, d₁ = 945 kg/m³
The human density after exhaling, d₂ = 1020 kg/m³
Therefore the average human density, d = 982.5 kg/m³
The density of the dead sea, D = 1230 kg/m³
The percentage of density of human body to the dead sea is,
P % = (982.5 / 1230) x 100 %
= 80 %
Therefore, the human body has 80% of dead sea density.
Hence, 20% of the human body float above the surface in the dead sea.
There's supposed to be a blank in the statement, where the answer is supposed to be inserted.
The question is supposed to say: "A wave is a disturbance that carries ______ from one place to another through matter or space".
To answer the question, write the word "<em>energy</em>" in the blank.