Answer:
--- Velocity
--- Distance
Explanation:
Given
--- Initial velocity
Solving (a): Velocity after 2.3s
To do this, we use the first equation of motion
Where
So, the equation becomes:
Solving (b): Distance covered in 2.3s
We make use of:
This gives:
Answer:
p_{f} = 6 m / s
Explanation:
We can solve this exercise using conservation of momentum. For this we define a system formed by the two balls, so that the forces during the collision have been intense and the moment is preserved
Initial instant. Before the crash
p₀ = m v +0
Final moment. Right after the crash
= (m + m) v_{f}
how the moment is preserved
p₀ = p_{f}
m v = 2 m v_{f}
v_{f} = v / 2
we calculate
v_{f} = 12/2
p_{f} = 6 m / s