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Nuetrik [128]
2 years ago
15

Match the type of boundary with its characteristic.

Physics
1 answer:
olga_2 [115]2 years ago
7 0

At Divergent boundary, Crust is created.

At Convergent boundary, Crust is destroyed.

At Transform boundary, Crust is neither created nor destroyed.

<h3>What occurs at Divergent, Convergent and Transform boundary?</h3>

A divergent boundary occurs when two tectonic plates move away from each other. At this boundary, new oceanic crust is created.

Convergent boundaries are those boundaries where two plates are pushing into each other. These boundaries are pushing one of the plates under the other and back into the mantle to melt.

Transform boundaries are places where plates slide sideways past each other. At this boundary, Crust is neither created nor destroyed.

Learn more about boundary here: brainly.com/question/14298823

#SPJ1

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Two inductors, L1 and L2, are in parallel. L1 has a value of 25 mH and L2 a value of 50 mH. The parallel combination is in serie
Bond [772]

Answer:

Explanation:

For parallel inductors ,

\frac{1}{L_R} = \frac{1}{L_1} +\frac{1}{L_2}

\frac{1}{L_R} =\frac{1}{25} +\frac{1}{50}

L_R=16.67 mH.

For series combination

Total inductance

= 16.67 + 20

= 36.67 mH .

reactance of total inductance at 300 kHz

= ωL_{total} where ω is angular frequency

= 2πfL_{total}

= 2 x 3.14 x 300 x 10³ x 36.67 x 10⁻³

= 69.1 x 10³ ohm

Total rms current = Vrms / reactance

= 60 / 69.1 x 10³ A

= .87 x 10⁻³ A

= .87 mA

7 0
2 years ago
Determine the minimum applied force p required to move wedge a to the right. the spring is compressed a distance of 175 mm. negl
BARSIC [14]
<span>b. The coefficient of static friction for all contacting surfaces is μs=0.35. neglect friction at the rollers.

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6 0
3 years ago
A 91.0-kg hockey player is skating on ice at 5.50 m/s. another hockey player of equal mass, moving at 8.1 m/s in the
never [62]

The momentum before the collision velocity after the collision will be 1237.6 kg m/s² and 6.8 m/sec.

<h3>What is the law of conservation of momentum?</h3>

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

(m₁) is the mass of hockey player 1= 91.0-kg

(m₂) is the mass of hockey player 2=  91.0-kg

(u₁) is the velocity before collision of hockey player 1 = 5.50 m/s.

(u₂) is the velocity before the collision of hockey player 2=?

a)

Momentum before the collision;

\rm  m_1u_1 + m_2u_2 \\\\ 91.0 \times 5.50 + 91.0 \times 8.1 \\\\ 1237.6 kg m/s^2

Momentum before the collision = 1237.6 kg m/s².

b)

The velocity of the two hockey players after the collision from the law of conservation of the momentum as:

Momentum before collision = Momentum after the collision

1237.6 kg m/s² = (m₁+m₂)V

1237.6 kg m/s² =(2 ×91.0-kg )V

V=6.8 m/sec.

Hence, momentum before the collision velocity after the collision will be 1237.6 kg m/s² and 6.8 m/sec.

To learn more about the law of conservation of momentum refer;

brainly.com/question/1113396

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8 0
2 years ago
Which formula is used to find an object’s acceleration?
marissa [1.9K]

Answer:

Δv/Δt

Explanation:

I beat your game SAW.

8 0
2 years ago
An aluminum wing on a passenger jet is 35 m long when its temperature is 17°C. At what temperature would the wing be 3 cm (0.03
Mnenie [13.5K]

Answer:

53.32°C

Explanation:

Length of the aluminium wing = 35 m

Change in length of aluminium wing = 0.03 m

The linear expansion coefficient of aluminium \alpha =23.6\times 10^{-6}/^{\circ}C

We know that change in length is given by \Delta L=L\alpha \Delta T

So 0.03=35\times 23.6\times 10^{-6}\Delta T

\Delta T=36.32^{\circ}C

So final temperature =T_I+\Delta T=17+36.32=53.3196^{\circ}C

5 0
3 years ago
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