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2 years ago

7. How much work is done in moving a charge of 10 micro coulombs 1 meter along an equipotential of 10 volts?

2 answers:

8 0

It takes work to push charge through a change of potential.
There's no change of potential along an equipotential path,
so that path doesn't require any work.

Neporo4naja [7]2 years ago

7 0

0, since moving along an equipotential requires no work.

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I NEED HELP ON 2 QUESTIONS PLEASEEE

tino4ka555 [31]

Answer:

2) c) give-way vessel

3) a) With one short blast

Explanation:

2) A vessel that is required to take early substantial action to ensure avoiding collision called Give way vessel

In overtaking, the vessel intending to overtake is the Give-Way Vessel the vessel that is going to be overtaken is the Stand-On Vessel

Therefore, the correct option is c) give-way vessel

3) When vessels use sound signals in a meeting head on situation both vessel are Give-Way vessels and both vessel pass the each other by turning to the starboard side therefore they intend to pass each other on their port side requiring one short blast

Therefore, the correct option is a) With one short blast.

4 0

3 years ago

If you wanted to increase the gravitational force between two objects what would you do

adelina 88 [10]

Double the force on the object

6 0

3 years ago

Read 2 more answers

The motion of an object undergoing constant acceleration can be modeled by the kinematic equations. One such equation is xf=xi+v

Arturiano [62]

Answer:

a = 1.72 m/s²

Explanation:

The given kinematic equation is the 2nd equation of motion. The equation is as follows:

xf = xi + (Vi)(t) + (1/2)(a)t²

where,

xf = the final position = 5000 m

xi = the initial position = 1000 m

Vi = the initial velocity = 15 m/s

t = the time taken = 60 s

a = acceleration = ?

Therefore,

5000 m = 1000 m + (15 m/s)(60 s) + (1/2)(a)(60 s)²

5000 m = 1000 m + 900 m + a(1800 s²)

5000 m = 1900 m + a(1800 s²)

5000 m - 1900 m = a(1800 s²)

a(1800 s²) = 3100 m

a = 3100 m/1800 s²

a = 1.72 m/s²

5 0

2 years ago

Which of the following is an example of a force inertia push pull

Whitepunk [10]

A force can be considered a push or pull

hope this helps :)

8 0

2 years ago

Two golfers each hit a ball at the same speed, but one at 60 degrees with the horizontal and the other 30 degrees. a. Which ball

likoan [24]

Answer:

Therefore, both balls will hit the ground at the same distance from their respective starting points and at the same time.

Explanation:

Both balls will hit the ground at the same distance and at the same time assuming they both start at the same initial elevation from the ground.

We know that range in the projectile motion given as

$R=\dfrac{v_o^2sin2\theta}{g}$

sin 60° = sin 120° =0.866

Therefore, the maximum range will be identical assuming both golfers hit the ball at the same elevation from the ground.

As for the time...

Where v is 0 m/s (final velocity at highest point), v0 is the initial velocity (for both golfers) and is the acceleration due to gravity (-9.8 m/s^²). As you can see, the time it takes to get to the highest point is independent of the angle; it is only dependent on the initial velocity. Since both golfers hit the ball with the same speed, the time for the ball to reach the highest point will be the same. Also, since it's a parabola, you can multiply the time by 2 for each golfer to get the time it takes to hit the ground.

Therefore, both balls will hit the ground at the same distance from their respective starting points and at the same time.

5 0

3 years ago