estimate the the nearest half....
5/8....it is closer to 4/8(which is 1/2) then it is to 8/8(which is 1)...so we will round 5/8 to 1/2
8/9....it is closer to 9/9 (which is 1) then it is to 4.5/9 (which is half)...so we will round 8/9 to 1
" the product " means multiply
so 1 * 1/2 = 1/2 (or 0.50) <== estimate
actual : 5/8 * 8/9 = 5/9 (or 0.55) <== actual
Answer: The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is 0.596
Step-by-step explanation:
Since the weights of catfish are assumed to be normally distributed,
we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = weights of catfish.
µ = mean weight
σ = standard deviation
From the information given,
µ = 3.2 pounds
σ = 0.8 pound
The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is is expressed as
P(x ≤ 3 ≤ 5.4)
For x = 3
z = (3 - 3.2)/0.8 = - 0.25
Looking at the normal distribution table, the probability corresponding to the z score is 0.401
For x = 5.4
z = (5.4 - 3.2)/0.8 = 2.75
Looking at the normal distribution table, the probability corresponding to the z score is 0.997
Therefore,.
P(x ≤ 3 ≤ 5.4) = 0.997 - 0.401 = 0.596
Answer:
168 and 12
Step-by-step explanation:
use fractions for this think of it as 14/15x and 1/15x and x is 180 and solve from there
96% is the answer 100%/x%=125/120
(100/x)*x=(125/120)*x - we multiply both sides of the equation by x
100=1.04166666667*x - we divide both sides of the equation by (1.04166666667) to get x
100/1.04166666667=x
96=x
x=96
The answer is C.
(0, 3)
y = x + 3
3 = 0 + 3
3 = 3
(1, 4)
y = x + 3
4 = 1 + 3
4 = 4
(2, 5)
y = x + 3
5 = 2 + 3
5 = 5
