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3 years ago

11

PLEASE PLEASE HELP??!?

1 answer:

UNO [17]3 years ago

4 0

In the case of linear equations, the graph will always be a line. In contrast, a nonlinear equation may look like a parabola if it is of degree 2, a curvy x-shape if it is of degree 3, or any curvy variation thereof. While linear equations are always straight, nonlinear equations often feature curves.

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Let f and g be two functions whose second derivatives are defined. Then (f · g) '' = f · g '' + f '' · g. true or false?

Marianna [84]

I hope this helps you

8 0

2 years ago

Which shows the expression below in simplified form? (7.2 × 107) ÷ (9 × 104) A. 8 × 101 B. -1.8 × 102 C. 8 × 102 D. 8 × 104

Mariana [72]

(7.2 × 10^7) ÷ (9 × 10^4)

= (7.2 / 9) x 10^(7 - 4)

= 0.8 x 10^3

= 8 x 10^2

Answer

C. 8 × 10^2

5 0

3 years ago

Follow the steps to solve this equation. 3(2x + 6) – 4x = 2(5x – 2) + 6 1. Use the distributive property: 6x + 18 – 4x = 10x – 4

Yuliya22 [10]

Answer:

$x=2$ .

Step-by-step explanation:

We have been given an equation $3(2x+6)-4x=2(5x-2)+6$ . We are supposed to solve our given equation step by step.

Step 1: Use the distributive property.

$3\cdot 2x+3\cdot 6-4x=2\cdot 5x-2\cdot 2+6$

$6x+18-4x=10x-4+6$

Step 2: Combine like terms.

$6x-4x+18=10x-4+6$

$2x+18=10x+2$

Step 3: Use subtraction property of equality:

$2x-2x+18-2=10x-2x+2-2$

$16=8x$

Step 4: Use the division property of equality:

$\frac{16}{8}=\frac{8x}{8}$

$2=x$

Therefore, the solution of our given equation is $x=2$ .

8 0

3 years ago

Read 2 more answers

Kayla flips a quarter 200 times. She expects that

ehidna [41]

Answer:

Experimental probability is likely to be slightly different from theoretical probability.

Step-by-step explanation:

This is because there is a 50-50 chance, but it is unlikely to be exactly 100-100. That is just to hypothesis!

7 0

2 years ago

Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).

NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

$1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}$

Now, differentiate to obtain

$\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}$

$=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}$

To obtain the required form, extract a factor in both the numerator and denominator:

$\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)$

3 0

3 years ago