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liberstina [14]
4 years ago
7

The axis of symmetry for a quadratic equation can be found using the formula x =-b/2a , where a and b are coefficients in the qu

adratic equation and x represents the values along a vertical line on the coordinate plane. When the equation is solved for a, such that b is the numerator of the resulting fraction, what is the denominator of the fraction?

Mathematics
2 answers:
Eddi Din [679]4 years ago
6 0

Answer:

B

Step-by-step explanation:

a = -b/2x

djverab [1.8K]4 years ago
3 0

Answer:

2x

Step-by-step explanation:

Solve the equation for a as follows:

First multiply both sides by 2a:

(2a)x=-b and then divide both sides by 2x:

a=-\frac{b}{2x}

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Fittoniya [83]
∠1 and ∠2 are RIGHT ANGLES, VERTICAL ANGLES, and SUPPLEMENTARY ANGLES. 

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7 0
4 years ago
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Where is the point of discontinuity of y =<br> -4x+81/x-2<br> ?
Genrish500 [490]

Answer:

x = 2

Step-by-step explanation:

y = \frac{-4x+81}{x-2}

If the denominator is equal to zero , then y is undefined.

this discontinuity can be found by equating the denominator to zero and solving for x.

x - 2 = 0 ⇒ x = 2 is the point of discontinuity

4 0
2 years ago
Mila buys 1112 pound of almonds and 56 pound of pecans.
AleksandrR [38]

Answer:

THIS MAKES NO SENCE

Step-by-step explanation:

6 0
3 years ago
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Find the equation for the line that passes through the point (1,-3) and that is parallel to the line with the equation 3/2x-2y=-
kondaur [170]

The equation for the line that passes through the point (1,-3) and that is parallel to the line with the equation \frac{3}{2}x - 2y = \frac{-17}{2} is:

y = \frac{3}{4}x - \frac{15}{4}

<h3><u>Solution:</u></h3>

Given that line that passes through the point (1, -3) and that is parallel to the line with the equation \frac{3}{2}x - 2y = \frac{-17}{2}

We have to find equation of line

<em><u>The slope intercept form is given as:</u></em>

y = mx + c

Where "m" is the slope of line and "c" is the y-intercept

Let us first find slope of line containing equation \frac{3}{2}x - 2y = \frac{-17}{2}

\frac{3}{2}x - 2y = \frac{-17}{2}

Rearrange the above equation into slope intercept form

\frac{3x}{2} + \frac{17}{2} = 2y\\\\y = \frac{3x}{4} + \frac{17}{4}

On comparing the above equation with slope intercept form y = mx + c,

m = \frac{3}{4}

So the slope of line containing equation \frac{3}{2}x - 2y = \frac{-17}{2} is m = \frac{3}{4}

We know that slopes of parallel lines are equal

So the slope of line parallel to line having above equation is also m = \frac{3}{4}

<em><u>Now let us find the equation of line having slope m = 3/4 and passes through point (1 , -3)</u></em>

Substitute m = \frac{3}{4} and (x, y) = (1 , -3) in slope intercept form

y = mx + c

-3 = \frac{3}{4}(1) + c\\\\c = -3 - \frac{3}{4}\\\\c = \frac{-15}{4}

<em><u>Thus the required equation of line is:</u></em>

substitute m = \frac{3}{4} and c = \frac{-15}{4} in slope intercept form

y = \frac{3}{4}x + \frac{-15}{4}\\\\y =\frac{3}{4}x - \frac{15}{4}

Thus the equation of line is found out

3 0
3 years ago
Maurice's teacher asked him to compare the mean and median of the data distribution explain and correct Maurice's error in compa
Dmitry_Shevchenko [17]

The first part where he mentions "The distribution is skewed right" is correct. The tail on the right hand side is pulled longer than it should be, or longer compared to the left tail. "Right skew" or "skewed right" is the same as "positively skewed". They all mean the same thing.

The portion where Maurice says "This implies that the mean is less than the median" is incorrect. This is where his error is located. The reason for the error is because it should be "The mean is greater than the median" when we have right-skewed data like this.

Here's one example to see why this is the case. Consider the distribution {1,2,3,4,5}. We can see that the median is 3 since it's directly in the center. The mean is also 3 since we add up all the values and divide by 5. Symmetric data has mean = median. Now, we'll replace the '5' with something much larger to get a large outlier. Let's say we have the set {1,2,3,4,55}. The median is still 3. The outlier doesn't pull on the median. However, the mean has changed and it is (1+2+3+4+55)/5 = 65/5 = 13. The mean went from 3 to 13. Therefore, mean > median here. The mean is affected by outliers. Think of it like the outlier is pulling on the mean in a sort of magnetic way. This outlier makes the mean larger than it should be. If the outlier is extreme enough, then it sometimes makes sense to consider the trimmed mean as opposed to the regular arithmetic mean. The trimmed mean is the mean of the main cluster of values ignoring the outlier(s).

-----------------------

To recap:

If we have right skewed data, then mean > median

As you can probably guess, if we had left-skewed data, then mean < median. In symmetric data, mean = median.

4 0
3 years ago
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