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Zina [86]
3 years ago
7

Fram Algebraic expression for the followinga)Two times a number increase by three​

Mathematics
1 answer:
Effectus [21]3 years ago
3 0

Answer:

2x + 3

Step-by-step explanation:

Let the number be x

2x + 3

Hope it helps :)

Please mark my answer as the brainliest

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Simplify the expression:
Lelu [443]
\cfrac{(12-5)^7}{\left((3+4)^2\right)^2}= \cfrac{7^7}{(7^2)^2} =\cfrac{7^7}{7^4}=7^{7-4}=7^3=343
5 0
3 years ago
At the bake sale the students earned $48.81. If there were 3 students how much did each student earn
Contact [7]

Answer:

Each student earned $16.27.

Step-by-step explanation:

48.81 / 3 = 16.27

5 0
3 years ago
Read 2 more answers
How do you simply 3(x+3)-2x
kiruha [24]
3(x+3)-2x
Distribute the 3
3x+9-2x
Combine like terms
x+9
Set equal to zero if you need to do this part
x+9=0
Get x by itself
x=-9
8 0
3 years ago
Employer A is offering you a position for $350000 per year l. Employer B is offering the same job for $18.00 per hour. Assuming
ss7ja [257]

Answer:

Depends

Step-by-step explanation:

In order to see which annual salary is higher, we must calculate the annual salary of B to compare to A. To do this, if B offers $18.00 an hour for 40 hours a week, that's $720 a week. Now to convert this to annual, multiply the weekly earnings by the 52 weeks in a year. Employer B offers $720 × 52 weeks = $37,440 annually. Assuming you didn't have a typo, $350,000 is $312,560 greater meaning A pays more. If you did have a typo, and meant that Employer A offered $35,000, then Employer B would pay more.

5 0
3 years ago
A simple random sample of 60 households in city 1 is taken. In the sample, there are 45 households that decorate their houses wi
murzikaleks [220]

Answer:

The calculated value of z = - 0.197  falls in the critical region therefore we reject the null hypothesis and conclude that  at  the 5% significance level there is significant difference in population proportions of households that decorate their houses with lights for the holidays

Step-by-step explanation:

We formulate the null and alternative hypotheses as

H0: p1= p2 there is no difference in population proportions of households that decorate their houses with lights for the holidays

against Ha : p1≠ p2  (claim)  ( two sided)

The significance level is set at ∝= 0.05

The critical value for two tailed test at alpha=0.05 is ± 1.96

or Z∝= 0.05/2= ± 1.96

The test statistic is

Z = p1-p2/√pq(1/n1 +1/n2)

p1= proportions of households  decorating in city 1  = 45/60=0.75

p2= proportions of households  decorating in city 2 = 40/50= 0.8

p = the common proportion on the assumption that the two proportion are same.

p =   \frac{n_1p_1 +n_2p_2}{n_1+n_2}

Calculating

p =60 (0.75) + 50 (0.8) / 110

p=  45+ 40/110= 85/110 = 0.772

so  q = 1-p= 1- 0.772= 0.227

Putting the values in the test statistic and calculating

z= 0.75- 0.8/ √0.772*0.227( 1/60 + 1/50)

z= -0.05/√ 0.175244 ( 110/300)

z= -0.05/0.25348

z= -0.197

The calculated value of z = - 0.197  falls in the critical region therefore we reject the null hypothesis and conclude that  at  the 5% significance level there is significant difference in population proportions of households that decorate their houses with lights for the holidays

4 0
3 years ago
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