GCF of 28y^4 and 20y^3 is 4y^3
Answer:
B.
Step-by-step explanation:
For this case we use the formula of distance between points.
We have then:
d = root ((x2-x1) ^ 2 + (y2-y1) ^ 2)
For AB:
AB = root ((4 - (- 1)) ^ 2 + (4-3) ^ 2)
AB = 5.099019514
For AC:
AC = root ((8 - (- 1)) ^ 2 + (1-3) ^ 2)
AC = 9.219544457
For BC:
BC = root ((8-4) ^ 2 + (1-4) ^ 2)
BC = 5
We observe that it has three sides with different dimensions, therefore, the triangle is scalene.
Answer:
Scalene
Answer:
I cant see that
Step-by-step explanation:
Answer:
5 units down
Step-by-step explanation:
