To find how much Henry can expect to receive from Social Security on a monthly basis, we first need to find how much he cant expect to receive from social security per year.
We know form our problem that Henry averaged an annual salary of $45,620, so to find how much can Henry expect to receive from Social Security per year, we just need to find the 42% of $45,620.
To find the 42% of $45,620, we are going to convert 42% to a decimal by dividing it by 100%, and then we are going to multiply the resulting decimal by $45,620:
Social security annual payment = (0.42)($45,620) = $19,160.40
Since there are 12 month in a year, we just need to divided the social security annual payment by 12 to find how much he can expect to receive each month.
Social security monthly payment = 
= $1.596.70
We can conclude that Henry can expect to receive $1.596.70 monthly from Social Security.
A perfect square must be hidden within all of those radicands in order to simplify them down to what the answer is.
.
.
. The rules for adding radicals is that the index has to be the same (all of our indexes are 2 since we have square roots), and the radicands have to be the same. In other words, we cannot add the square root of 4 to the square root of 5. They either both have to be 4 or they both have to be 5. So here's what we have thus far:
. We can add
and
to get
. That means as far as our answer goes, A = 72 and B = 4, or (72, 4), choice a.
Answer:
Step-by-step explanation:
The area of a rectangle(A) related to the length (L) and WITDH (W) of its sides by the following Relationship:A=L W if you know the width is easy to find the length rearranging this equation to get L=A÷w if you know the length and want width rearranged to get W=A÷L this is the formula not the answer.
Answer: The answer is 
Step-by-step explanation: Given that the area of the whole circle is represented by the expression
We are to find the area of the outer ring of the circle, i.e., to find the circumference of the circle.
Now, if 'r' represents the radius of the circle, then we have
Thus, the area of the outer ring is
