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m_a_m_a [10]
4 years ago
14

Help please.. I need all the answers

Mathematics
2 answers:
Wewaii [24]4 years ago
4 0
I hope this helps you

qaws [65]4 years ago
4 0
I can't really see the paper it's slanted a little.
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marissa [1.9K]
Part A x^2-3x -4
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2 years ago
Find an equation of the circle that has center , 1−1 and passes through , 32
katovenus [111]

 

hello :<span>
<span>an equation of the circle Center at the A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a = 1  and b = -1 (Center at A (1 , -1) 
r = AP
r² = (AP)²    ....... P(3,2)
r² = (3-1)² +(2+1)² = 4+9=13
an equation of the circle that satisfies the stated conditions.
Center at </span></span>A (1 , -1)  , passing through P(3, 2) is :  (x-1)² + (y+1)² = 13²

6 0
3 years ago
(а^2+2)(а-1)-а(а^2+2) Help me, please.
Arlecino [84]
Expand?

(a^2+2)(a-1)-a(a^2+2) \\ \\ a^3 - a^2 + 2a - 2 - a^3 - 2a \\ \\ (a^3 - a^3) - a^2 + (2a - 2a) - 2 \\ \\ -a^2 - 2 \\ \\

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4 0
3 years ago
(11^-4)^-6=11^?<br><br> I need to find out what the question mark is
lara [203]
Use:\\(a^n)^m=a^{n\cdot m}\\\\\left(11^{-4}\right)^{-6}=11^x\\\\11^{(-4)(-6)}=11^x\\\\11^{24}=11^x\Rightaarow x=24

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4 years ago
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torisob [31]
1/4 more................................................
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