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marshall27 [118]
3 years ago
9

Find an equation of the circle that has center , 1−1 and passes through , 32

Mathematics
1 answer:
katovenus [111]3 years ago
6 0

 

hello :<span>
<span>an equation of the circle Center at the A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a = 1  and b = -1 (Center at A (1 , -1) 
r = AP
r² = (AP)²    ....... P(3,2)
r² = (3-1)² +(2+1)² = 4+9=13
an equation of the circle that satisfies the stated conditions.
Center at </span></span>A (1 , -1)  , passing through P(3, 2) is :  (x-1)² + (y+1)² = 13²

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