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Tamiku [17]
3 years ago
13

Determine the equation of a circle having a diameter with endpoints at (12,-14) and(2,4)

Mathematics
1 answer:
snow_lady [41]3 years ago
3 0
Center of a circle is a midpoint of line connecting two endpoints so center is:
(12,-14) (2,4) we divide those two points by two 
C(a,b)- center
C(a,b)=((12+2)/2),(-14+4)/2)=(7,-5)
Radius is the distance from the center to any point on the circle:
we take point (2,4)
r=\sqrt{ (7-2)^{2} + (-5-4)^{2} } = \sqrt{25+81} = \sqrt{106}

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-----------------------------------------

Explanation:

The coefficients are -3 and 5. They are the numbers to the left of the variable terms
Multiply the coefficients to get -3*5 = -15. So -15 is the coefficient in the answer

Multiply the x terms to get x^3 times x = x^(3+1) = x^4. Notice the exponents are being added

Do the same for the y terms as well: y^2 times y^(-1) = y^(2+(-1)) = y^(2-1) = y^1 = y

So we have a final coefficient of -15, the x terms simplify to x^4 and the y terms simplify to just y

Put this all together and we end up with -15x^4y which is what choice C is showing

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