The balanced equation of the reaction is:
O3(g) + NO (g) → O2 (g) + NO2 (g)
Then the ratios of reaction is 1 mol O3 : 1 mol NO : 1 mol O2 : 1 mol NO2
If you have initially 0.05 M of O3 and 0.02 M of NO, the reaction will end when all the NO is consumed.
The by the stoichiometry 0.02 mol of O3 will be consumed in 8 seconds.
And the rate of reaction is change in concetration divided by the time.
The change in concentration in O3 is 0.02 M
Then, the rate respect O3 is 0.02 M / 8 seconds = 0.0025 M/s
O=C=O, it’s a double bond between the carbons and oxygen
The given question is incomplete. The complete question is as follows.
From the following formula, calculate the quantities required for each of the following ingredients to make 5 lb. (avoir) of hydrophilic ointment. All values to be in g, do not include units in your submitted answer; use no more than 3 decimal places. Convert using 1 lb = 454 g. Note: all values done by mass, including the water, so this is not a q.s situation (volume is irrelevant).
Methylparaben 0.25 g
Propylparaben 0.15 g
Sodium Lauryl Sulfate 10 g
Propylene Glycol 120 g
Stearyl Alcohol 240 g
White Petrolatum 250 g
Purified Water, to make 1000 g
Explanation:
For the given quantities, the sum is 620.4 g. Now, amount of purified water (to make 1000 g of ointment) is as follows.
1000 g - 620.4 g
= 379.6 g
Now, to make 5 lb we will calculate the quantities as follows.
Formula weight = 1000 g
Therefore, desired quantity is as follows.
5 lb = 5 x 454 g
= 2270 g
Hence, this means the factor is calculated as follows.
= 2.27
Now, we will calculate the quantity of each ingredient using factor 2.27 as follows.
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Methylparaben = 0.25 g x 2.27 = 0.5675 g
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Propylparaben = 0.15 g x 2.27 = 0.3405 g
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Sodium Lauryl Sulfate = 10 g x 2.27 = 22.7 g
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Propylene Glycol = 120 g x 2.27 = 272.4 g
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Stearyl Alcohol = 240 g x 2.27 = 544.8 g
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White Petrolatum = 250 g x 2.27 = 567.5 g
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Purified Water = 379.6 g x 2.27 = 861.692 g
MgH2 + 2 H2O → Mg(OH)2 + 2 H2