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iren [92.7K]
3 years ago
6

The same force is applied separately to two objects, A and B. B has twice the mass of A. What happens?

Chemistry
1 answer:
Alexeev081 [22]3 years ago
5 0

Answer:

B's acceleration is half that of A

Explanation:

The force equation is;

Force = mass × acceleration

According to Newton's second law of motion, which explains the relationship between acceleration and mass of an object, an inverse relationship exists between the mass and the acceleration. For the same amount of force, an increase in mass (m) means a constant decrease in acceleration (a) of the object. In other words, if the mass of an object increases by two times, the acceleration will decrease by two times.

In this case involving objects A and B which has the same amount of force applied, object B has TWICE the mass of A. Using Newton's second law, this means that object B's ACCELERATION WILL BE HALF OF THAT OF OBJECT A.

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Answer: 60 g C3H8O

Explanation: Solution:

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Oxygen O = 16 x 1

Molar mass = 60 g C3H8O

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4 years ago
Using the name of the ionic compound, select the appropriate chemical formula. Use the periodic table
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The compound Ammonium Phosphate is (NH4)3PO4 while that of sodium acetate is NaC2H3O2.

<h3>What is an ionic compound?</h3>

An ionic compound is  compound that is composed of ions. We know that a poly atomic ion is an ion that contains more than one atom.

Looking at the options that have been provided, we know that the correct formula for the compound Ammonium Phosphate is (NH4)3PO4 while that of sodium acetate is NaC2H3O2.

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3 years ago
Which of the following is an example of a way you can reduce personal consumption of resources?
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Answer:

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3 years ago
Calculation of ph from hydrogen ion concentration what is the ph of a solution that has an h1 concentration of (a) 1.75 3 1025 m
faltersainse [42]
<h2>Solutions:</h2>

<u>Case a:</u> Finding pH for [H⁺] = 1.75 × 10⁻⁵ mol/L :

As we know pH is given as,

                                  pH  = -log [H⁺]

Putting value,

                                  pH  = -log [1.75 x 10⁻⁵]

                                 pH =  4.75

<u>Case b:</u> Finding pH for [H⁺] = 6.50 × 10⁻¹⁰ mol/L :

As we know pH is given as,

                                  pH  = -log [H⁺]

Putting value,

                                  pH  = -log [6.50 × 10⁻¹⁰]

                                 pH =  9.18

<u>Case c:</u> Finding pH for [H⁺] = 1.0 × 10⁻⁴ mol/L :

As we know pH is given as,

                                  pH  = -log [H⁺]

Putting value,

                                  pH  = -log [1.0 × 10⁻⁴]

                                 pH =  4

<u>Case d:</u> Finding pH for [H⁺] = 1.50 × 10⁻⁵ mol/L :

As we know pH is given as,

                                  pH  = -log [H⁺]

Putting value,

                                  pH  = -log [1.50 × 10⁻⁵]

                                 pH =  4.82

7 0
3 years ago
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