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elena55 [62]
4 years ago
6

B) Ethane has the formula C2H6. In terms of electronic structure,

Chemistry
1 answer:
k0ka [10]4 years ago
5 0

Answer:

There is one single covalent bond between two carbon atoms.

Explanation:

We know that sharing of electrons form covalent bonds.

If we look upon K,L,M ,N shells of the carbon and hydrogen atoms.

We found that Hydrogen is having only  1 electron in K shell.

And Carbon on the other hand is having 2 electrons in K shell and 4 electrons in L shell.

So carbon have  4 valence electrons,and it can share 4 bonds with any relevant atom to complete its octet.

And Hydrogen requires  1 electron to complete its doublet.

Alkane general formula C_{n}H_{2n+2}

For ethane n=2

C_{2}H_{4+2} = C_{2}H_{6}

1 Carbon atom is shared by  3 Hydrogen.

The remaining one electron (4-3)=1 of carbon will be shared with another carbon atom.

An image of the sharing of electrons attached below,

Hence we have only  1 covalent bond between the two.

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Balance the equation:2Na+3H2O-2NaOH+H2​
aleksandrvk [35]

Answer:

2Na + 2H2O → 2NaOH + H2

Explanation:

A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge are the same for both the reactants and the products.

7 0
3 years ago
Question 2<br> How many significant figures does the number have?<br> 23.0702
Pavlova-9 [17]
The number 23.0702 has 6 significant figures.

To answer this, you must have the rules for significant figures,

1. All non-zero numbers ARE significant
2. Zeros between two non-zero digits ARE significant
3. Leading zeros are NOT significant
4. Trailing zeros are ONLY significant if the number has a decimal point

The number 23.0702 has 4 non-zero numbers(rule 1), and both zeros are between two non-zero digits(rule 2). Since all 6 figures in the number 23.0702 are significant, the number 23.0702 has 6 significant figures.
7 0
4 years ago
The answer and the work please​
Murljashka [212]

Answer:

for what?

Explanation:

8 0
3 years ago
The water-gas shift reaction plays a central role in the chemical methods for obtaining cleaner fuels from coal: CO(g) + H2O(g)
taurus [48]

<u>Answer:</u> The concentration of carbon dioxide, hydrogen gas, carbon monoxide and water when equilibrium is re-established are 0.362 M, 0.212 M, 0.138 M and 0.138 M respectively.

<u>Explanation:</u>

For the given chemical reaction:

CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)

The expression of K_c for above reaction follows:

K_c=\frac{[CO_2][H_2]}{[CO][H_2O]}         ........(1)

We are given:

[CO]_{eq}=[H_2O]_{eq}=[H_2]_{eq}=0.10M

[CO_2]_{eq}=0.40M

Putting values in above equation, we get:

K_c=\frac{0.40\times 0.10}{010\times 0.10}\\\\K_c=4

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Moles of hydrogen gas = 0.30 mol

Volume of solution = 2.0 L

Putting values in above equation, we get:

\text{Molarity of }H_2=\frac{0.30mol}{2L}=0.15M

When hydrogen gas is added, the concentration of product gets increased. But, by Le-Chatelier's principle, the equilibrium will shift in the direction where concentration of product must decrease, which is in the backward direction.

Concentration of hydrogen gas when equilibrium is re-established = 0.1 + 0.15 = 0.25 M

Now, the equilibrium is shifting to the reactant side. The equation follows:

                      CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)

Initial:              0.1      0.1                 0.4       0.1

At eqllm:       0.1+x   0.1+x           0.4-x      0.25-x

Putting values in expression 1, we get:

4=\frac{(0.25-x)(0.4-x)}{(0.1+x)(0.1+x)}\\\\3x^2+1.45x-0.06=0\\\\x=0.038,-0.522

Neglecting the negative value of 'x'

Calculating the concentrations of the species:

Concentration of carbon dioxide = (0.4 - x) = (0.4 - 0.038) = 0.362 M

Concentration of hydrogen gas = (0.25 - x) = (0.25 - 0.038) = 0.212 M

Concentration of carbon monoxide = (0.1 + x) = (0.1 + 0.038) = 0.138 M

Concentration of water = (0.1 + x) = (0.1 + 0.038) = 0.138 M

Hence, the concentration of carbon dioxide, hydrogen gas, carbon monoxide and water when equilibrium is re-established are 0.362 M, 0.212 M, 0.138 M and 0.138 M respectively.

8 0
3 years ago
5. How would you calculate the pH (NOT POH) of a base when given<br><br> the concentration of [OHJ?
PIT_PIT [208]

Answer:

pOH = -log₁₀ [OH-]

pH = 14 - pOH

Explanation:

First of all, calculate the value of pOH from  the hydroxide concentration do this using the equation below;

pOH = -log₁₀ [OH-]

After obtaining the pOH, calculate pH using the equation below:

pH + pOH = 14

pH = 14 - pOH

3 0
3 years ago
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