3 years ago

0.65 repeating as a decimal

Mathematics

1 answer:

vladimir1956 [14]3 years ago

5 0

If .65 were to repeat it would be .656565656565656

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Paha777 [63]

I only have one and it's 180-65=angle2 angle2=angle1 so 180-65=angle1

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4 years ago

Which set of side lengths is a Pythagorean triple?<br> 1,3,10<br> 4,5,9<br> 9, 40, 41<br> 16, 30, 44

Elina [12.6K]

Answer:

Which set of side lengths is a Pythagorean triple? 9, 40, 41

Step-by-step explanation:

$c = \sqrt{ {a}^{2} + {b}^{2} }$

9 = a

40 = b

41 = c

$c = \sqrt{ {a}^{2} + {b}^{2} } \\ c = \sqrt{ {9}^{2} + {40}^{2} } \\ c = \sqrt{81 + 1.600} \\ c = \sqrt{1.681} \\ c = 41$

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3 years ago

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yKpoI14uk [10]

Answer:

Step 1: 14x − 21 = 1; Step 2: 14x = 22

Explanation:

7(2x−3)=1

Step 1: Simplify both sides of the equation

7(2x−3)=1

(7)(2x)+(7)(−3)=1(Distribute)

14x+−21=1

14x−21=1

Step 2: Add 21 to both sides

14x−21+21=1+21

14x=22

Step 3: Divide both sides by 14

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3 years ago

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The boiling point of jet fuel is 329°

natka813 [3]

Since, the boiling point of jet fuel = 329 °F

We have to convert the boiling point of jet fuel in $^\circ C$ .

The expression which is used to convert $^\circ F$ to $^\circ C$ is given by:

C = $\frac{5}{9}(F-32)$

= $\frac{5}{9}(329-32)$

= $\frac{5}{9}(297)$

= 165 $^\circ C$

Therefore, the boiling point of jet fuel is 165 $^\circ C$ .

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kykrilka [37]

Answer:

4 is the answer

Step-by-step explanation:

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