Answer:
free throws = 6
2 points shots = 3
Step-by-step explanation:
To do this we will have 2 incognitas.
x = number of free throws
y = number of shots of 2 points
x(1) + y(2) = 12
he says he made twice as many free throws as 2 points
x = 2y
2y(1) + y(2) = 12
2y + 2y = 12
4y = 12
y = 12/4
y = 3
x = 2y
x = 2*3
x = 6
free throws = 6
2 points shots = 3
In order to hop 8 units, you can do:
1 two-units hops, 2 three-units hops
4 two-units hops
1 one-unit hops, 2 two-units hops, 1 three-units hops
2 one-unit hops, 2 three-units hops
2 one-unit hops, 3 two-units hops
3 one-unit hops, 1 two-units hops, 1 three-units hops
4 one-unit hops, 2 two-units hops
5 one-unit hops, 1 three-units hops
6 one-unit hops, 1 two-units hops
8 one-unit hops
It’s the first one -13–16
Answer:
Your answer is: Look Below
Step-by-step explanation:
Hope this helped : )
Answer:
Dimensions of the rectangular plot will be 500 ft by 750 ft.
Step-by-step explanation:
Let the length of the rectangular plot = x ft.
and the width of the plot = y ft.
Cost to fence the length at the cost $3.00 per feet = 3x
Cost to fence the width of the cost $2.00 per feet = 2y
Total cost to fence all sides of rectangular plot = 2(3x + 2y)
2(3x + 2y) = 6,000
3x + 2y = 3,000 ----------(1)
3x + 2y = 3000
2y = 3000 - 3x
y = ![\frac{1}{2}[3000-3x]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B3000-3x%5D)
y = 1500 - 
Now area of the rectangle A = xy square feet
A = x[
]
For maximum area 
A' =
= 0
1500 - 3x = 0
3x = 1500
x = 500 ft
From equation (1),
y = 1500 - 
y = 1500 - 750
y = 750 ft
Therefore, for the maximum area of the rectangular plot will be 500 ft × 750 ft.
two fencing 3(500+500) = $3000
other two fencing 2(750+750) = $3000