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Schach [20]
2 years ago
8

Identify the linear function graph

Mathematics
1 answer:
IRINA_888 [86]2 years ago
5 0

Answer:

B is a linear function graph, the others are not

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MAVERICK [17]

Answer: .

Step-by-step explanation:

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3 years ago
What is the answer to question 17
Nikolay [14]

Answer:

It is 1/1536

Step-by-step explanation:

You divide 1/512 by three since it is a cube.

6 0
3 years ago
if angle 1 and angle 2 form a linear pair. if m<1=5x+9 and m<2=3x+11, find the measure of both angles
Ulleksa [173]

Answer: m\angle 1=109\°\\m\angle 2=71\°

Step-by-step explanation:

It is important to remember the definition of "Linear pair angles".

By definitiion "Linear pair angles" are two angles which are adjacents and supplementary.

Based on this, we know that the angles \angle1 and \angle2 are supplementary, which means that they add up to 180 degrees.

So, knowing that:

m\angle 1=5x+9\\m\angle 2=3x+11

We can write the following expression and solve for "x":

(5x+9)+(3x+11)=180\\\\8x=180-20\\\\x=\frac{160}{8}\\\\x=20

Therefore, substituting, we get that the measures of the angles \angle1 and \angle2 are:

 m\angle 1=5(20)+9=109\°\\\\\\m\angle 2=3(20)+11=71\°

8 0
3 years ago
Show all work and reasoning
Natalija [7]
Split up the interval [2, 5] into n equally spaced subintervals, then consider the value of f(x) at the right endpoint of each subinterval.

The length of the interval is 5-2=3, so the length of each subinterval would be \dfrac3n. This means the first rectangle's height would be taken to be x^2 when x=2+\dfrac3n, so that the height is \left(2+\dfrac3n\right)^2, and its base would have length \dfrac{3k}n. So the area under x^2 over the first subinterval is \left(2+\dfrac3n\right)^2\dfrac3n.

Continuing in this fashion, the area under x^2 over the kth subinterval is approximated by \left(2+\dfrac{3k}n\right)^2\dfrac{3k}n, and so the Riemann approximation to the definite integral is

\displaystyle\sum_{k=1}^n\left(2+\frac{3k}n\right)^2\frac{3k}n

and its value is given exactly by taking n\to\infty. So the answer is D (and the value of the integral is exactly 39).
8 0
3 years ago
What two-dimensional shape is formed by a cross section of the cone shown from the vertex perpendicular to the base of the cone?
Ber [7]

The correct choice is D!

Hope this helped you out! :)

8 0
3 years ago
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