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4 years ago

Draw the skeleton structure of 3-methyl-2-hexanone or 3-methylhexan-2-one.

Chemistry

1 answer:

skad [1K]4 years ago

5 0

Both names are for same compound.
Let's draw structure for <span>3-methyl-2-hexanone.

In name the last words i.e. hexanone means that the parent chain is made up of six carbons (hexa = 6) and the word -one means ketone. So, this is a six carbon chain containing carbonyl group. The position of carbonyl group is at position 2 (2-hexanone).

Then comes the substituents, the number at the start of the name specifies the position of substiuent (i.e. 3, at position 3) and the substituent attached at position 3 is methyl.

The structure is as follow,</span>

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The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In t

Digiron [165]

Answer:

35.3124 g is the maximum mass of $H_2O$ that can be produced.

Explanation:

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Mass of $NH_3$ = 52.3 g

Molar mass of $NH_3$ = 17.031 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{52.3\ g}{17.031\ g/mol}$

$Moles\ of\ NH_3= 3.0709\ mol$

Given mass of $O_2$ = 52.3 g

Molar mass of $O_2$ = 31.9898 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{52.3\ g}{31.9898\ g/mol}$

$Moles\ of\ O_2=1.6349\ mol$

According to the given reaction:

$4NH_3+5O_2\rightarrow 4NO_4+6H_2O$

4 moles of $NH_3$ reacts with 5 moles of $O_2$

1 mole of $NH_3$ reacts with 5/4 moles of $O_2$

Also,

3.0709 moles of $NH_3$ reacts with $\frac{5}{4}\times 3.0709$ moles of $O_2$

Moles of $O_2$ = 3.8386 moles

Available moles of $O_2$ = 1.6349 moles

Limiting reagent is the one which is present in small amount. Thus, $O_2$ is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

5 moles of $O_2$ on reaction forms 6 moles of $H_2O$

1 mole of $O_2$ on reaction forms 6/5 moles of $H_2O$

Thus,

1.6349 mole of $O_2$ on reaction forms $\frac{6}{5}\times 1.6349$ moles of $H_2O$

Moles of $H_2O$ = 1.9618 moles

Molar mass of $H_2O$ = 18 g/mol

Mass of sodium sulfate = Moles × Molar mass = 1.9618 × 18 g = 35.3124 g

<u> 35.3124 g is the maximum mass of $H_2O$ that can be produced.</u>

3 0

3 years ago

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HELP ASAP

AlexFokin [52]

Suitable hypothesis for the experiment is as temperature increases rate of reaction also increases.

<h3>What is rate of reaction?</h3>

Rate of any reaction gives idea about the speed of the completion of that reaction.

Rate of reaction will be affected by many factors are some such factors are:

Dependent variable: Rate of change of the chemical species which are present in the reaction is the dependent variables.
Independent variable: Independent variable is temperature as it does not depends on the rate, in spite of this rate depends on temperature.
Controlled variables: Environment of the reaction, amount of catalyst, light exposure to the reactions are the controlled variables as it depends on the requirement of the amount of product.

Hence, hypothesis is as temperature increases rate of reaction also increases.

To know more about rate of reaction, visit the below link:

brainly.com/question/19513092

#SPJ2

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Which aqueous solution of Kl freezes at the lowest temperature?

shtirl [24]

The correct answer is B.
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For example the least amount of water in the greatest amount of salt.

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3 years ago

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ikadub [295]

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