3 years ago

What is the molarity of a solution containing 60. grams of NaOH dissolved in 400. mL of water?

Chemistry

1 answer:

Hunter-Best [27]3 years ago

8 0

Answer: 3.75 M

Explanation:

400 mL = 0.4 L

NaOH has a molar mass of around 40 g/mol.

$\frac{60 grams}{40 g/mol}$ = 1.5 moles

Molarity = $\frac{1.5 moles}{0.4 Liters}$ = 3.75 M

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erastova [34]

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$[Ag^{+}]=4.2\times 10^{-2}M$

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Ksp of BaCrO4 = 1.1 x 10^-10

$BaCrO_4 (s)\leftrightharpoons Ba^{2+}(aq)\;+\;CrO_{4}^{2-}(aq)$

$Ksp=[Ba^{2+}][CrO_{4}^{2-}]$

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$[CrO_{4}^{2-}]=\frac{1.2\times 10^{-10}}{(0.20)}= 6.0\times 10^{-10}$

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$Ag_{2}CrO_4(s) \leftrightharpoons 2Ag^{+}(aq)\;+\;CrO_{4}^{2-}(aq)$

$Ksp=[Ag^{+}]^{2}[CrO_{4}^{2-}]$

$1.1\times 10^{-12}=[Ag^{+}]^{2}](6.0\times 10^{-10})$

$[Ag^{+}]^{2}]=\frac{1.1\times 10^{-12}}{(6.0\times 10^{-10})}= 1.8\times 10^{-3}$

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So, BaCrO4 will start precipitating when [Ag+] is 4.2 x 1.2^-2 M

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