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erica [24]
2 years ago
9

A new radio station, KHEM-AM, broadcasts

Chemistry
1 answer:
Serga [27]2 years ago
7 0

Answer:

wavelength = 345.62 m

Explanation:

Given that,

Frequency of signal, f = 868 kHz

We need to find the wavelength of its signal.

The relation between wavelength and frequency is given by :

c=f\lambda

c is speed of light

\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{868\times 10^3}\\\\\lambda=345.62\ m

So, the wavelength of its signal is 345.62 m

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H2 + Br2 → 2HBr If 2.23 g of hydrogen (H2) reacts completely, how many grams of hydrogen bromide (HBr) is formed? (mw Br=79.9) Q
NemiM [27]

Answer:

The correct option is;

B) 179 g

Explanation:

The parameters given are;

Mass of H₂ that takes part in the reaction = 2.23 g

Molar mass of hydrogen gas, H₂ = 2.016 g

Number of moles, n, of hydrogen gas H₂ is given by the relation;

n = \dfrac{Mass \ of \ hydrogen \ gas, \, H_2 }{Molar \ mass \ of  \, H_2 } = \dfrac{2.23}{2.016} = 1.106 \ moles

Chemical equation for the reaction;

H₂ + Br₂ → 2HBr

Given that one mole of H₂ reacts with one mole of Br₂ to produce two moles of HBr

1.106 mole of H₂ will react with 1.106 mole of Br₂ to produce 2 × 1.106 which is 2.212 moles of HBr

The molar mass, of HBr = 80.91 g/mol

The mass of HBr produced = Molar mass of HBr × Number of moles of HBr

The mass of HBr produced = 80.91 × 2.212 = 178.997 g ≈ 179 grams

Therefore, the correct option is B) 179 g.

3 0
3 years ago
Why can more sugar be dissolved in hot water than cold water (more solute be dissolved in hot solvent then cold solvent)
lesantik [10]
Sugar dissolves faster in hot water than it does in cold water because hot water has more energy than cold water. when water is heated, the molecules gain energy and because of that, move faster. as they move faster, they come in contact with the sugar more often, causing it to dissolve faster.
4 0
3 years ago
Classify the following statements as observation, inference, prediction, measuring or classifying
Nadusha1986 [10]

Answer:

ggghy I am a great and the other hand the wildcats their own is the name of the

8 0
3 years ago
A 10,0-L cylinder of gas is stored at room temperature (20.0°C) and a pressure of 1800 psi. If the gas is
makvit [3.9K]

Considering the Charles' law, the gas would have a temperature of -109.2 C.

<h3>Charles' law</h3>

Finally, Charles' law establishes the relationship between the volume and temperature of a gas sample at constant pressure. This law says that the volume is directly proportional to the temperature of the gas. That is, if the temperature increases, the volume of the gas increases, while if the temperature of the gas decreases, the volume decreases.

Charles' law is expressed mathematically as:

\frac{V}{T} =k

If you want to study two different states, an initial state 1 and a final state 2, the following is true:

\frac{V1}{T1} =\frac{V2}{T2}

<h3>Temperature of the gas in this case</h3>

In this case, you know:

  • P1= 1800 psi
  • V1= 10 L
  • T1= 20 C= 293 K (being 0 C= 273 K)
  • P2= 1800 psi
  • V2= 6 L
  • T2= ?

You can see that the pressure remains constant, so you can apply Charles's law.

Replacing in the Charles's law:

\frac{10 L}{293 K} =\frac{6 L}{T2}

Solving:

\frac{10 L}{293 K} T2=6 L

T2=\frac{6 L}{\frac{10 L}{293 K} }

<u><em>T2=163.8 K= -109.2 C</em></u>

The gas would have a temperature of -109.2 C.

Learn more about Charles's law:

brainly.com/question/4147359?referrer=searchResults

7 0
3 years ago
A cylindrical glass tube of length 27.4cm and radius 4 cm is filled with gas. The empty tube has a mass of 254.3 g. The tube fil
Temka [501]

Density of the gas is 3.05 × 10⁻³ g / cm³.

<u>Explanation:</u>

Volume of the cylinder = π r² h

where r is the radius and h is the height of the height or the length of the glass tube.

Here r = 4 cm and h = 27.4 cm

Volume of the cylinder = 3.14 × 4 × 4 × 27.4 = 1376.6 cm³

We have to find the mass of the gas by subtracting the mass of the tube filled with the substance from the mass of the empty tube.

Mass of the substance = 258.5 - 254.3 = 4.2 g

We have to find the density using the formula as,

$ Density = \frac{mass}{volume}

Plugin the values as,

$ Density = \frac{4.2}{1376.6}

              = 3.05 × 10⁻³ g / cm³

So the Density of the gas is 3.05 × 10⁻³ g / cm³.

3 0
3 years ago
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