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2 years ago

A new radio station, KHEM-AM, broadcasts

Chemistry

1 answer:

Serga [27]2 years ago

7 0

Answer:

wavelength = 345.62 m

Explanation:

Given that,

Frequency of signal, f = 868 kHz

We need to find the wavelength of its signal.

The relation between wavelength and frequency is given by :

$c=f\lambda$

c is speed of light

$\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{868\times 10^3}\\\\\lambda=345.62\ m$

So, the wavelength of its signal is 345.62 m

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What is the molarity of a hydrochloric acid solution, when 30.0 mL is neutralized by 48.0 mL of 0.100 mol/L

bulgar [2K]

The molarity of a hydrochloric acid solution : 0.32 M

<h3>Further explanation </h3>

Titration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution).

Titrations can be distinguished including acid-base titration, depositional titration, and redox titration. An acid-base titration is the principle of neutralization of acids and bases is used.

Acid-base titration formula

Ma. Va. na = Mb. Vb. nb

Ma, Mb = acid base concentration

Va, Vb = acid base volume

na, nb = acid base valence

1 ⇒HCl (valence=1, HCl ⇒H⁺+Cl⁻, one H⁺)

2⇒Ca(OH)₂(valence=2, Ca(OH)₂⇒Ca²⁺+2OH⁻, two OH⁻)

M₂=0.1 M

V₂=48 ml=0.048 L

V₁=30 ml=0.03 L

$\tt M_1.V_1.n_1=M_2.V_2.n_2\\\\M_1\times 0.03\times 1=0.1\times 0.048\times 2\\\\M_1=0.32$

3 0

3 years ago

Help me plsss

Yuki888 [10]

Answer:

8.34

Explanation:

1) how much moles of NH₃ are in the reaction;

2) how much moles of H₂ are in the reaction;

3) the required mass of the H₂.

all the details are in the attachment; the answer is marked with red colour.

Note1: M(NH₃) - molar mass of the NH₃, constant; M(H₂) - the molar mass of the H₂, constant; ν(NH₃) - quantity of NH₃; ν(H₂) - quantity of H₂.

Note2: the suggested solution is not the shortest one.

8 0

3 years ago

Aaliya knows that sliced apples turn brown when left out in the open air. She also knows that pouring certain liquids on then wi

fenix001 [56]

An apple should be cut into 4 equal pieces, then put each slice in a separate container and label accordingly with letters A, B, C, and Control. Put water, ginger ale, and lemon juice into containers A, B, and C respectively but leave the Control untouched. Observe which of the slices in containers A, B, C will stay the same color after the one in control turns brown, if the slice maintains its color then the liquid added prevents an apple slice from browning. The variables are the liquids added and the control is the slice that did not have anything added to it.

7 0

3 years ago

How are saturated and supersaturated solutions similar?

Serggg [28]

Answer:

They are similar in sense that both cannot dissolve any more solid unless heat or other factors are added. For eg if a solution is saturated it can no longer dissolve the given substance. But if the solution is heated, the solid will dissolved this is now said to be supersaturated.

Explanation:

4 0

3 years ago

How much water would be needed to completely dissolve 1.52 L of the gas at a pressure of 730 torr and a temperature of 21 ∘C?

Sophie [7]

Answer:

The correct answer is 0.4 L.

Explanation:

The mentioned question can be solved by using the equation,

C = K × Pgas--------(i)

Here K is the Henry law constant whose value is 0.158 mol/L/atm, C is the concentration of the gas in liquid state, and Pgas is the partial pressure of the gas.

Now to find the volume of water, the formula to be used is,

PV = nRT-----------(ii)

Here P is the pressure of the gas, V is the volume, R is the universal gas constant whose value is 0.082 Latm/mol/K and T is the temperature.

PgasV = nRT

Pgas = nRT/Vgas

The value of Pgas is inserted in equation (i) we get,

C = K × nRT/Vgas

It is to be noted that C = n/V, here n is the no. of the moles and V is the volume of liquid.

n/Vliquid = K × nRT/Vgas

1/Vliquid = KRT/Vgas

Vliquid = Vgas/KRT--------------(iii)

Based on the given information, the volume of the gas is 1.52 L, the value of K is 0.158 mol/L/atm, the value of R is 0.082 Latm/mol/K and value of T is 21 degree C or 273 + 21 = 294 K.

Now putting the values in equation (iii) we get,

Vliquid = 1.52 L / 0.158 × 0.082 × 294

Vliquid = 1.52 / 3.809

Vliquid = 0.399 or 0.4 L

Hence, the volume of water required to dissolve 1.52 L of gas is 0.4 L.

8 0

3 years ago