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Tatiana [17]
3 years ago
15

Simplify 7 square root of 3-4 square root of 6 plus square root of 48 minus square root of 54

Mathematics
1 answer:
raketka [301]3 years ago
6 0

Answer:

B) 11√3 - 7√6

Step-by-step explanation:

√48 can be simplified to <em>4√3</em>, and √54 can be simplified to <em>3√6</em>.

The equation is now <em>7√3 - 4√6 + 4√3 - 3√6</em>.

This can be grouped into <em>(7√3 + 4√3) + (-4√6 -3√6)</em>.

We get 11√3 - 7√6.

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Evgesh-ka [11]

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hope this helps

3 0
3 years ago
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Alexxandr [17]
To take out terms outside the radical we need to divide the power of the term by the index of the radical; the quotient will be the power of the term outside the radical, and the remainder will be the power of the term inside the radical. 
First, lets factor 8:
8=2 ^{3}
Now we can divide the power of the term, 3, by the index of the radical 2:
\frac{3}{2} = 1 with a remainder of 1
Next, lets do the same for our second term x^{7}:
\frac{7}{2} = 3 with a remainder of 1
Again, lets do the same for our third term y^{8}:
\frac{8}{2} =4 with no remainder, so this term will come out completely.

Finally, lets take our terms out of the radical:
\sqrt{8x^{7} y^{8}  }= \sqrt{ 2^{3} x^{7} y^{8}   }  =2 x^{3}  y^{4}  \sqrt{2x}

We can conclude that the correct answer is the third one. 

4 0
3 years ago
Read 2 more answers
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