Answer:
width = 3.5 m
length = 18 m
Step-by-step explanation:
area = length x width
x is the width then length = 2x + 11
x(2x + 11) = 63
2x^2 + 11x - 63 = 0
The formula to solve a quadratic equation of the form ax^2 + bx + c = 0 is equal to x = [-b +/-√(b^2 - 4ac)]/2a
with a = 2
b = 11
c = -63
substitute in the formula
x = [-11 +/- √(11^2 - 4(2)(-63))]2(2)
x = [-11 +/- √(121 + 504)]/4
x = [-11 +/- √625]/4
x = (-11 +/- 25)/4
x1 = (-11 + 25)/4 = 14/4 = 3.5
x2 = (-11 - 25)/4 = -36/4 = -9
since width can't be a negative number, x is 3.5
length = 2x + 11 = 2(3.5) + 11 = 18
<span>What is the arc length when Θ=3 pi/5 and the radius is 7 cm?
</span><span>Here are the available answers...
21pi/5 cm
12pi/5 cm
6pi/5 cm
3pi/35 cm
</span>
Given:
arc length = theta * radius
arc length = (3 pi/5)(7cm)
arc length = 21pi/5 cm Answer is the 1st option.
Answer:
31.25
Step-by-step explanation:
Answer:
84
Step-by-step explanation:
