Hello!
hint: we can rewrite your function as below:
<span>3/<span>tan<span>(<span>4x−3π</span>) = </span></span></span>3(1+tan4xtan3π)/tan4x−tan3π =
=<span>3/<span>tan<span>(<span>4x</span>) = </span></span></span>3cot<span>(<span>4x</span><span>)
</span></span>now, since the period P of cotangent function is pi, then the period of cot(4x), which is the period of our original function, is such that:
<span>"4P=π"
Hope this Helps! Have A Wonderful Day! :)</span>
A. Y= -7
X=2
4x+2y=-6
+(3x-2y=-8
1 - 5x < 24
Hope this helps you
Brainliest would be appreciated
-AaronWiseIsBae
