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s2008m [1.1K]
3 years ago
5

Describe the nature of the roots for this equation

Mathematics
1 answer:
vitfil [10]3 years ago
5 0

First, fint the roots of the equation 2x^2+5x-7=0.

1.

D=5^2-4\cdot 2\cdot (-7)=25+56=81,\\\sqrt{D}=\sqrt{81}=9,\\ \\x_1=\dfrac{-5-9}{2\cdot 2}=-\dfrac{14}{4}=-3.5,\\ \\x_2=\dfrac{-5+9}{2\cdot 2}=\dfrac{4}{4}=1.

2. You can see that this equation has two different real roots. Note that you can make this statement without finding roots, only knowing the value of discriminant: since D=81>0, then the equation has two different real roots.

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Answer:

The correct option is;

D. F(x) = x⁴ - x² + 2

Step-by-step explanation:

From the graph, we have;

The y-intercept =  2, therefore, when x = 0, y = 2

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The possible function is F(x) = x⁴ + x² + 2 and F(x) = 2 - x⁴ - x²

The roots of the function, F(x) = x⁴ - x² + 2, is given as follows;

0 = x⁴ - x² + 2

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For F(x) = 2 - x⁴ - x², we have;

0 = 2 - x⁴ - x²

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