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3 years ago

Please Help Me! 50 points!

Mathematics

2 answers:

mariarad [96]3 years ago

7 0

Move to the left 2 units would be a translation

Then Flip arms up and down is rotation.

Hope this helps.

ANTONII [103]3 years ago

5 0

Hello,

Question-

Answer-#1 Translation

#2 Rotation

Important- If my answer was enough to help you pleasr mark me as brainliest, leave a thanks, and rate my answer 5 stars thank you and have the best day ever!

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Can anyone please help me?

sasho [114]

Answer: I can't see if

Step-by-step explanation: Hope this notifys u

6 0

3 years ago

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Amy has 2 rows of 4 sports trophies on each of her 3 shelves. how many trophies does she have in all?

sleet_krkn [62]

Each shelf holds 8 trophies (2X4=8). 3 shelves times 8 trophies will equal a total of 24 trophies.

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3 years ago

If M is the midpoint of segment AB, then which of the following statements is/are true? AB=MB AM=MB Segment AM is congruent to s

Archy [21]

AB is the large segment.

AM is half of the large segment.

MB is the second half of the large segment.

AM = MB is true.

Segment AM is congruent to segment MB is true.

AB = MB is false.

3 0

3 years ago

Jake’s dad is 6 more than 3 times Jake’s age. The sum of their ages is 42 . Find their ages. Use whole numbers.

kati45 [8]

Answer: Jake is 9 and his dad is 33.

Step-by-step explanation: 9x3=27+6=33 9+33=42

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3 years ago

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Use the given degree of confidence and sample data to construct interval for the population proportion. Of 369 randomly selected

Alexxx [7]

Answer:

e) (3.77%, 8.70%)

95% confidence interval for the percentage of all medical students who plan to work in a rural community

(3.83% , 8.69%)

95% confidence level for the population proportion who blame oil companies for the recent increase in gasoline prices

(0.406 , 0.454)

Step-by-step explanation:

Step(i):-

Given random sample size 'n' = 369

Sample proportion

$p = \frac{x}{n} = \frac{23}{369} = 0.0623$

95% confidence intervals are determined by

$(p^{-} - Z_{0.05} \sqrt{\frac{p(1-p)}{n} } , p^{-} + Z_{0.05} \sqrt{\frac{p(1-p)}{n} })$

$(0.0623 - 1.96 \sqrt{\frac{0.0623(1-0.0623)}{369} } , 0.0623 + 1.96\sqrt{\frac{0.0623(1-0.0623)}{369} })$

(0.0623 - 0.0246 , 0.0623 + 0.0246)

(0.0383 , 0.0869)

(3.83% , 8.69%)

95% confidence interval for the percentage of all medical students who plan to work in a rural community

(3.83% , 8.69%)

Step(ii):-

Given 43% of those polled blamed of companies the most for the recent increase in gasoline prices

sample proportion 'p' = 0.43

Given Margin of error (M.E) = 0.024

95% confidence intervals are determined by

$(p^{-} - Z_{0.05} \sqrt{\frac{p(1-p)}{n} } , p^{-} + Z_{0.05} \sqrt{\frac{p(1-p)}{n} })$

$(0.43 - 0.024 } , 0.43 +0.024 )$

(0.406 , 0.454)

Final answer:-

95% confidence level for the population proportion who blame oil companies for the recent increase in gasoline prices

(0.406 , 0.454)

6 0

3 years ago