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sergiy2304 [10]

2 years ago

11

What is the area of each parallelogram

1 answer:

iren [92.7K]2 years ago

8 0

Answer:

24cm^2

Step-by-step explanation:

A=bh

a=base x height..

8 x 3=24cm (^2 because its area)

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2d(3*6)=48y when y=1/4

vaieri [72.5K]

Answer: d = 1/3

Step-by-step explanation: 48y = 48/4 = 12. So, 2d(18) is equal to 12. 12/18 is 2/3 so 2d has to equal 2/3. That means d = 1/3.

8 0

2 years ago

Ratio of dolls to teddy bears is 6:5. If the has 240 dolls how many teddy bears are there?

scZoUnD [109]

Answer:
There will be 200 teddy bears.

Explanation:
Please check the picture attached!

I hope this helps!

8 0

3 years ago

Read 2 more answers

Find the sum and simplify

statuscvo [17]

<u>Answer</u>:

[ ( 2 x^2 - x - 5 ) ] / [ ( x + 2 ) ( x - 3 ) ]

option c). is correct.

<u>Step-by-step explanation</u>:

( x + 1 ) / ( x + 2 ) + ( x - 1 ) / ( x - 3 )

= > [ ( x + 1 ) ( x - 3 ) + ( x - 1 ) ( x + 2 ) ] / [ ( x + 2 ) ( x - 3 ) ]

= > [ ( x^2 - 3 x + x - 3 + x^2 + 2 x - x - 2 ) ] / [ ( x + 2 ) ( x - 3 ) ]

= > [ ( 2 x^2 - x - 5 ) ] / [ ( x + 2 ) ( x - 3 ) ]

Hence we get required answer!

6 0

2 years ago

Order these numbers from LEAST to GREATEST. A) 2, 11 /8 , 7 /4 B) 7 /4 , 11 /8 , 2 C) 11 /8 , 7 /4 , 2 D) 11 /8 , 2, 7 /4

Nezavi [6.7K]

Answer: 11/8. 7/4. 2

Step-by-step explanation:

7 0

3 years ago

Find all points on the x-axis that are 14 units from the point (4, -7).

BaLLatris [955]

Answer:

The points are: (16.12,0),(-8.12,0).

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

Distance between two points:

Suppose we have two points, $(x_1,y_1)$ and $(x_2,y_2)$ . The distance between them is given by:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Find all points on the x-axis that are 14 units from the point (4, -7).

Being on the x-axis mean that they have y-coordinate equal to 0, so the point is (x,0).

The distance is 14. So

$\sqrt{(x-4)^2+(0-(-7))^2} = 14$

$\sqrt{x^2 - 8x + 16 + 49} = 14$

$\sqrt{x^2 - 8x + 65} = 14$

$(\sqrt{x^2 - 8x + 65})^2 = 14^2$

$x^2 - 8x + 65 - 196 = 0$

$x^2 - 8x - 131 = 0$

So $a = 1, b = -8, c = -131$

$\bigtriangleup = (-8)^{2} - 4(1)(-131) = 588$

$x_{1} = \frac{-(-8) + \sqrt{588}}{2} = 16.12$

$x_{1} = \frac{-(-8) - \sqrt{588}}{2} = -8.12$

The points are: (16.12,0),(-8.12,0).

4 0

2 years ago