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poizon [28]
3 years ago
13

A dog runs from point O to B. The dog reaches A at 2.3 s into the sprint. Then the dog reaches C at 4.1 s. What is the average v

elocity of the dog from A to C?
will give brainliest

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
6 0

We are given

A dog runs from point O to B

t(OA)=2.3 s

t(OC)=4.1 s

now, we can find time between A and C

t(AC)=t(OC)-t(OA)

t(AC)=4.1-2.3

t(AC)=1.8 s

we are given

distance between A and C is 4m

so,

d=4m

now, we can find average velocity between A and C

v=\frac{d}{t}

we can plug values

v=\frac{4}{1.8}

v=2.2m/s

so, option-C..................Answer

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Answer:

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Step-by-step explanation:

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2 years ago
What is the value of the expression (5)³?​
NemiM [27]

Answer:

125

Step-by-step explanation:

5 times 5 is 25. 25 times 5 is 125.

7 0
3 years ago
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The length of a rectangle is 3 in more than twice it’s width, and it’s area is 65 sq in. What is it’s width?
likoan [24]

Answer: 5 inches.

Step-by-step explanation:

The  formula for calculate the area of a rectangle is:

A=w*l

Where l is the length and w is the width.

If  the length of a rectangle is 3 inches more than twice it’s width, then:

l=2w+3

Substitute l=2w+3 and the area into the formula and solve for the width:

65=(2w+3)w\\65=2w^2+3w\\0=2w^2+3w-65

Use the quadratic formula:

w=\frac{-b\±\sqrt{b^2-4ac}}{2a}\\\\w=\frac{-3\±\sqrt{3^2-4(2)(-65)}}{2(2)}\\\\w=5\\w=-6.5

Choose the positive value.

Therefore, the width is: 5 inches.

4 0
3 years ago
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to tell whether the relationship is a proportional relationship if so than give the constant of proportionality
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There is a relationship between if you notice all of the x values or numbers of minutes are being multiplied by 60 

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8 0
3 years ago
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Identifying and Graphing Sequences: lesson 4-1
goldfiish [28.3K]

Answer:

1) Domain: {   1,2,3,4,5,6}

Range: {12,24,36,48,60,72}

2) First four terms are: 2,5,8,11

3) First four terms are: 8,13,20,29

4) First four terms are: 0,0,2,6

5) First four terms are: 0,1,1.41,1.73

Step-by-step explanation:

1.

n       1      2     3     4      5      6

f(n)    12    24    36   48    60    72

Domain: {   1,2,3,4,5,6}

Range: {12,24,36,48,60,72}

Write first four terms of each sequence

2) f(n)=3n-1

Put n = 1, 3(1)-1 = 3-1 = 2

Put n = 2, 3(2)-1 = 6-1 = 5

Put n = 3, 3(3)-1 = 9-1 = 8

Put n = 4, 3(4)-1 = 12-1 = 11

So, First four terms are: 2,5,8,11

3) f(n)=n^2+2n+5

Put n = 1, (1)^2+2(1)+5= 1+2+5 = 8

Put n = 2, (2)^2+2(2)+5 = 4+4+5= 13

Put n = 3, (3)^2+2(3)+5 = 9+6+5 = 20

Put n = 4, (4)^2+2(4)+5 = 16+8+5 = 29

So, First four terms are: 8,13,20,29

4) f(n)=(n-1)(n-2)

Put n = 1, (1-1)(1-2) = 0(-1) = 0

Put n = 2, (2-1)(2-2) = 1(0) = 0

Put n = 3, (3-1)(3-2) = 2(1) = 2

Put n = 4, (4-1)(4-2) = 3(2) = 6

So, First four terms are: 0,0,2,6

5) f(n) = \sqrt{n-1}

Put n=1 \sqrt{1-1}=\sqrt{0}=0

Put n=2 \sqrt{2-1}=\sqrt{1}=1

Put n=3 \sqrt{3-1}=\sqrt{2}= 1.41

Put n=4 \sqrt{4-1}=\sqrt{3}=1.73

So, First four terms are: 0,1,1.41,1.73

8 0
3 years ago
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