Question

A dog runs from point O to B. The dog reaches A at 2.3 s into the sprint. Then the dog reaches C at 4.1 s. What is the average velocity of the dog from A to C?
will give brainliest

Answer 1

We are given

A dog runs from point O to B

t(OA)=2.3 s

t(OC)=4.1 s

now, we can find time between A and C

t(AC)=t(OC)-t(OA)

t(AC)=4.1-2.3

t(AC)=1.8 s

we are given

distance between A and C is 4m

so,

d=4m

now, we can find average velocity between A and C

$v=\frac{d}{t}$

we can plug values

$v=\frac{4}{1.8}$

$v=2.2m/s$

so, option-C..................Answer